Edexcel AEA 2005 June — Question 3 9 marks

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2005
SessionJune
Marks9
PaperDownload PDF ↗
TopicChain Rule
TypeFind curve equation from derivative
DifficultyHard +2.3 This AEA question requires recognizing an incorrect application of the chain rule (the given formula is wrong—it should be the product rule), then correctly applying the product rule to solve a differential equation with an initial condition. This demands strong conceptual understanding, error identification, and multi-step integration techniques beyond standard A-level.
Spec1.08k Separable differential equations: dy/dx = f(x)g(y)

3.Given that $$\frac { \mathrm { d } } { \mathrm {~d} x } ( u \sqrt { } x ) = \frac { \mathrm { d } u } { \mathrm {~d} x } \times \frac { \mathrm { d } ( \sqrt { } x ) } { \mathrm { d } x } , \quad 0 < x < \frac { 1 } { 2 }$$ where \(u\) is a function of \(x\) ,and that \(u = 4\) when \(x = \frac { 3 } { 8 }\) ,find \(u\) in terms of \(x\) .
(9)

3.Given that

$$\frac { \mathrm { d } } { \mathrm {~d} x } ( u \sqrt { } x ) = \frac { \mathrm { d } u } { \mathrm {~d} x } \times \frac { \mathrm { d } ( \sqrt { } x ) } { \mathrm { d } x } , \quad 0 < x < \frac { 1 } { 2 }$$

where $u$ is a function of $x$ ,and that $u = 4$ when $x = \frac { 3 } { 8 }$ ,find $u$ in terms of $x$ .\\
(9)\\

\hfill \mbox{\textit{Edexcel AEA 2005 Q3 [9]}}