| Exam Board | Edexcel |
|---|---|
| Module | AEA (Advanced Extension Award) |
| Year | 2003 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Topic | Reciprocal Trig & Identities |
| Type | Express in terms of one function |
| Difficulty | Challenging +1.2 This question requires converting between trig functions (sec to cos, sin 2θ to 2sinθcosθ), algebraic manipulation, and solving a resulting equation. While it involves multiple steps and careful algebraic work, the techniques are standard for A-level. The AEA context suggests slightly elevated difficulty, but the problem follows a clear path once you multiply through by cos²θ and substitute tan θ = sin θ/cos θ. |
| Spec | 1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals |
2.Find the values of $\tan \theta$ such that
$$2 \sin ^ { 2 } \theta - \sin \theta \sec \theta = 2 \sin 2 \theta - 2 .$$
\hfill \mbox{\textit{Edexcel AEA 2003 Q2 [8]}}