Edexcel AEA 2020 June — Question 2 13 marks

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2020
SessionJune
Marks13
PaperDownload PDF ↗
TopicComposite & Inverse Functions
TypeDetermine domain for composite
DifficultyChallenging +1.8 This AEA question requires understanding of composite function domains, exponential/logarithmic manipulation to simplify gf(x), finding where a circle is tangent to a line (perpendicular distance formula), and multi-step reasoning across parts. While systematic, it demands careful domain analysis and geometric insight beyond standard A-level, though the algebraic manipulations themselves are routine once the approach is identified.
Spec1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence1.03d Circles: equation (x-a)^2+(y-b)^2=r^21.06a Exponential function: a^x and e^x graphs and properties1.06d Natural logarithm: ln(x) function and properties

2.The functions \(f\) and \(g\) are defined by $$\begin{array} { l l } \mathrm { f } ( x ) = 2 \sqrt { 1 - \mathrm { e } ^ { - x } } & x \in \mathbb { R } , x \geqslant 0 \\ \mathrm {~g} ( x ) = \ln \left( 4 - x ^ { 2 } \right) & x \in \mathbb { R } , - 2 < x < 2 \end{array}$$
    1. Explain why fg cannot be formed as a composite function.
    2. Explain why gf can be formed as a composite function.
    1. Find \(\mathrm { gf } ( x )\) ,giving the answer in the form \(\mathrm { gf } ( x ) = a + b x\) ,where \(a\) and \(b\) are constants.
    2. State the domain and range of gf.
  1. Sketch the graph of the function gf.
    On your sketch,you should show the coordinates of any points where the graph meets or crosses the coordinate axes. The circle \(C\) with centre \(( 0 , - \ln 9 )\) touches the line with equation \(y = \operatorname { gf } ( x )\) at precisely one point.
  2. Find an equation of the circle \(C\) .

2.The functions $f$ and $g$ are defined by

$$\begin{array} { l l } 
\mathrm { f } ( x ) = 2 \sqrt { 1 - \mathrm { e } ^ { - x } } & x \in \mathbb { R } , x \geqslant 0 \\
\mathrm {~g} ( x ) = \ln \left( 4 - x ^ { 2 } \right) & x \in \mathbb { R } , - 2 < x < 2
\end{array}$$
\begin{enumerate}[label=(\alph*)]
\item \begin{enumerate}[label=(\roman*)]
\item Explain why fg cannot be formed as a composite function.
\item Explain why gf can be formed as a composite function.
\end{enumerate}\item \begin{enumerate}[label=(\roman*)]
\item Find $\mathrm { gf } ( x )$ ,giving the answer in the form $\mathrm { gf } ( x ) = a + b x$ ,where $a$ and $b$ are constants.
\item State the domain and range of gf.
\end{enumerate}\item Sketch the graph of the function gf.\\
On your sketch,you should show the coordinates of any points where the graph meets or crosses the coordinate axes.

The circle $C$ with centre $( 0 , - \ln 9 )$ touches the line with equation $y = \operatorname { gf } ( x )$ at precisely one point.
\item Find an equation of the circle $C$ .
\end{enumerate}

\hfill \mbox{\textit{Edexcel AEA 2020 Q2 [13]}}