Edexcel AEA 2002 Specimen — Question 7

Exam BoardEdexcel
ModuleAEA (Advanced Extension Award)
Year2002
SessionSpecimen
TopicTrig Proofs

7.The variable \(y\) is defined by $$y = \ln \left( \sec ^ { 2 } x + \operatorname { cosec } ^ { 2 } x \right) \text { for } 0 < x < \frac { \pi } { 2 } .$$ A student was asked to prove that $$\frac { \mathrm { d } y } { \mathrm {~d} x } = - 4 \cot 2 x .$$ The attempted proof was as follows: $$\begin{aligned} y & = \ln \left( \sec ^ { 2 } x + \operatorname { cosec } ^ { 2 } x \right)
& = \ln \left( \sec ^ { 2 } x \right) + \ln \left( \operatorname { cosec } ^ { 2 } x \right)
& = 2 \ln \sec x + 2 \ln \operatorname { cosec } x
\frac { \mathrm {~d} y } { \mathrm {~d} x } & = 2 \tan x - 2 \cot x
& = \frac { 2 \left( \sin ^ { 2 } x - \cos ^ { 2 } x \right) } { \sin x \cos x }
& = \frac { - 2 \cos 2 x } { \frac { 1 } { 2 } \sin 2 x }
& = - 4 \cot 2 x \end{aligned}$$ (a)Identify the error in this attempt at a proof.
(b)Give a correct version of the proof.
(c)Find and simplify a general relationship between \(p\) and \(q\) ,where \(p\) and \(q\) are variables that depend on \(x\) ,such that the student would obtain the correct result when differentiating \(\ln ( p + q )\) with respect to \(x\) by the above incorrect method.
(d)Given that \(p ( x ) = k \sec r x\) and \(q ( x ) = \operatorname { cosec } ^ { 2 } x\) ,where \(k\) and \(r\) are positive integers,find the values of \(k\) and \(r\) such that \(p\) and \(q\) satisfy the relationship found in part(c). \section*{END} Marks for presentation: 7
TOTAL MARKS: 100