OCR FP1 2007 January — Question 3 6 marks

Exam BoardOCR
ModuleFP1 (Further Pure Mathematics 1)
Year2007
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSequences and series, recurrence and convergence
TypeStandard summation formulae application
DifficultyModerate -0.3 This is a straightforward algebraic manipulation question requiring expansion of r(r-1)(r+1) to r³-r, then applying two standard summation formulae and factorising. It's slightly easier than average as it's a direct application of given formulae with minimal problem-solving, though the algebraic manipulation and factorisation require some care.
Spec4.06a Summation formulae: sum of r, r^2, r^3

3 Use the standard results for \(\sum _ { r = 1 } ^ { n } r\) and \(\sum _ { r = 1 } ^ { n } r ^ { 3 }\) to find $$\sum _ { r = 1 } ^ { n } r ( r - 1 ) ( r + 1 ) ,$$ expressing your answer in a fully factorised form.

AnswerMarks Guidance
\(\frac{1}{4}n^2(n+1)^2 - \frac{1}{2}n(n+1)\)M1 Expand to obtain \(r^3 - r\)
M1Consider difference of two standard results
A1Obtain correct unfactorised answer
M1Attempt to factorise
A1Obtain factor of \(\frac{1}{4}n(n+1)\)
\(\frac{1}{4}n(n-1)(n+1)(n+2)\)A1 Obtain correct answer
$\frac{1}{4}n^2(n+1)^2 - \frac{1}{2}n(n+1)$ | M1 | Expand to obtain $r^3 - r$

| M1 | Consider difference of two standard results

| A1 | Obtain correct unfactorised answer

| M1 | Attempt to factorise

| A1 | Obtain factor of $\frac{1}{4}n(n+1)$

$\frac{1}{4}n(n-1)(n+1)(n+2)$ | A1 | Obtain correct answer
3 Use the standard results for $\sum _ { r = 1 } ^ { n } r$ and $\sum _ { r = 1 } ^ { n } r ^ { 3 }$ to find

$$\sum _ { r = 1 } ^ { n } r ( r - 1 ) ( r + 1 ) ,$$

expressing your answer in a fully factorised form.

\hfill \mbox{\textit{OCR FP1 2007 Q3 [6]}}