7 Fig. 7 shows the curve with parametric equations
$$x = \cos \theta , y = \sin \theta - \frac { 1 } { 8 } \sin 2 \theta , 0 \leqslant \theta < 2 \pi$$
The curve crosses the \(x\)-axis at points \(\mathrm { A } ( 1,0 )\) and \(\mathrm { B } ( - 1,0 )\), and the positive \(y\)-axis at C . D is the maximum point of the curve, and E is the minimum point.
The solid of revolution formed when this curve is rotated through \(360 ^ { \circ }\) about the \(x\)-axis is used to model the shape of an egg.
\begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{5dcd4f44-4c61-4384-be1b-a8d63cb6b5aa-4_744_1207_776_431}
\captionsetup{labelformat=empty}
\caption{Fig. 7}
\end{figure}
- Show that, at the point \(\mathrm { A } , \theta = 0\). Write down the value of \(\theta\) at the point B , and find the coordinates of C .
- Find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(\theta\).
Hence show that, at the point D,
$$2 \cos ^ { 2 } \theta - 4 \cos \theta - 1 = 0 .$$
- Solve this equation, and hence find the \(y\)-coordinate of D , giving your answer correct to 2 decimal places.
The cartesian equation of the curve (for \(0 \leqslant \theta \leqslant \pi\) ) is
$$y = \frac { 1 } { 4 } ( 4 - x ) \sqrt { 1 - x ^ { 2 } } .$$
- Show that the volume of the solid of revolution of this curve about the \(x\)-axis is given by
$$\frac { 1 } { 16 } \pi \int _ { - 1 } ^ { 1 } \left( 16 - 8 x - 15 x ^ { 2 } + 8 x ^ { 3 } - x ^ { 4 } \right) \mathrm { d } x .$$
Evaluate this integral.