OCR C3 2008 June — Question 2 5 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2008
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFunction Transformations
TypeMultiple separate transformations (sketch-based, modulus involved)
DifficultyModerate -0.3 This is a straightforward function transformation question requiring students to apply standard rules: reflecting in y=x for inverse functions and applying a vertical stretch with reflection for -2f(x). While it requires careful attention to coordinate transformations, these are routine C3 techniques with no problem-solving insight needed, making it slightly easier than average.
Spec1.02v Inverse and composite functions: graphs and conditions for existence1.02w Graph transformations: simple transformations of f(x)

2 \includegraphics[max width=\textwidth, alt={}, center]{5c501214-b41c-43a8-b9c6-986758e83e7d-2_529_855_397_646} The diagram shows the graph of \(y = \mathrm { f } ( x )\). It is given that \(\mathrm { f } ( - 3 ) = 0\) and \(\mathrm { f } ( 0 ) = 2\). Sketch, on separate diagrams, the following graphs, indicating in each case the coordinates of the points where the graph crosses the axes:
  1. \(y = \mathrm { f } ^ { - 1 } ( x )\),
  2. \(y = - 2 \mathrm { f } ( x )\).

2\\
\includegraphics[max width=\textwidth, alt={}, center]{5c501214-b41c-43a8-b9c6-986758e83e7d-2_529_855_397_646}

The diagram shows the graph of $y = \mathrm { f } ( x )$. It is given that $\mathrm { f } ( - 3 ) = 0$ and $\mathrm { f } ( 0 ) = 2$. Sketch, on separate diagrams, the following graphs, indicating in each case the coordinates of the points where the graph crosses the axes:\\
(i) $y = \mathrm { f } ^ { - 1 } ( x )$,\\
(ii) $y = - 2 \mathrm { f } ( x )$.

\hfill \mbox{\textit{OCR C3 2008 Q2 [5]}}