OCR C3 2005 June — Question 5 8 marks

Exam BoardOCR
ModuleC3 (Core Mathematics 3)
Year2005
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyStandard +0.3 This is a standard two-part harmonic form question requiring routine application of the R sin(θ + α) method followed by solving a trigonometric equation. While it involves multiple steps (finding R and α, then solving), both parts follow textbook procedures with no novel insight required, making it slightly easier than the average A-level question.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

5
  1. Express \(3 \sin \theta + 2 \cos \theta\) in the form \(R \sin ( \theta + \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\).
  2. Hence solve the equation \(3 \sin \theta + 2 \cos \theta = \frac { 7 } { 2 }\), giving all solutions for which \(0 ^ { \circ } < \theta < 360 ^ { \circ }\).

AnswerMarks Guidance
(i) Obtain \(R = \sqrt{13}\), or 3.6 or 3.61 or greater accuracyB1
Attempt recognisable process for finding \(\alpha\)M1 [allow sine/cosine muddles]
Obtain \(\alpha = 33.7\)A1 Total: 3 marks [or greater accuracy]
(ii) Attempt to find at least one value of \(\theta + \alpha\)*M1 [following their \(R\)]
Obtain value rounding to 76 or 104A1∨
Subtract their \(\alpha\) from at least one valueM1 [dependent on *M]
Obtain one value rounding to 42 or 43, or to 70A1
Obtain other value 42.4 or 70.2A1 Total: 5 marks [or greater accuracy; no other answers between 0 and 360; ignore answers outside 0 to 360]
**(i)** Obtain $R = \sqrt{13}$, or 3.6 or 3.61 or greater accuracy | B1 |

Attempt recognisable process for finding $\alpha$ | M1 | [allow sine/cosine muddles]

Obtain $\alpha = 33.7$ | A1 | Total: 3 marks [or greater accuracy]

**(ii)** Attempt to find at least one value of $\theta + \alpha$ | *M1 | [following their $R$]

Obtain value rounding to 76 or 104 | A1∨ |

Subtract their $\alpha$ from at least one value | M1 | [dependent on *M]

Obtain one value rounding to 42 or 43, or to 70 | A1 |

Obtain other value 42.4 or 70.2 | A1 | Total: 5 marks [or greater accuracy; no other answers between 0 and 360; ignore answers outside 0 to 360]
5 (i) Express $3 \sin \theta + 2 \cos \theta$ in the form $R \sin ( \theta + \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$.\\
(ii) Hence solve the equation $3 \sin \theta + 2 \cos \theta = \frac { 7 } { 2 }$, giving all solutions for which $0 ^ { \circ } < \theta < 360 ^ { \circ }$.

\hfill \mbox{\textit{OCR C3 2005 Q5 [8]}}