Edexcel M2 — Question 5 9 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Marks9
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TopicMomentum and Collisions 1
TypeParticle brought to rest by collision
DifficultyStandard +0.3 This is a standard M2 collision problem requiring application of conservation of momentum and Newton's restitution law. Part (a) involves straightforward algebraic manipulation of two equations to show a given result. Part (b) requires simple inequality reasoning using the constraint 0 < e ≤ 1 and 0 < λ < 1/2. While it involves multiple steps, the techniques are routine for M2 students and the 'show that' format provides the target answer.
Spec6.03b Conservation of momentum: 1D two particles6.03j Perfectly elastic/inelastic: collisions6.03k Newton's experimental law: direct impact

5. A smooth sphere \(S\) of mass \(m\) is moving with speed \(u\) on a smooth horizontal plane. The sphere \(S\) collides with another smooth sphere \(T\), of equal radius to \(S\) but of mass \(k m\), moving in the same straight line and in the same direction with speed \(\lambda u , 0 < \lambda < \frac { 1 } { 2 }\). The coefficient of restitution between \(S\) and \(T\) is \(e\). Given that \(S\) is brought to rest by the impact,
  1. show that \(e = \frac { 1 + k \lambda } { k ( 1 - \lambda ) }\).
  2. Deduce that \(k > 1\).

Question 5:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(mu + km\lambda u = kmv\)M1 A1 Conservation of momentum
\(\frac{u}{k}(1 + k\lambda) = v\)
\(v = e(u - \lambda u) = eu(1-\lambda)\)M1 A1 Newton's law of restitution
\(\Rightarrow \frac{u}{k}(1+k\lambda) = eu(1-\lambda)\)M1
\(\Rightarrow \dfrac{(1+k\lambda)}{k(1-\lambda)} = e\)A1 (6)
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\dfrac{1+k\lambda}{k(1-\lambda)} \leq 1 \Rightarrow 1 + k\lambda \leq k(1-\lambda)\)M1
\(\Rightarrow \dfrac{1}{1-2\lambda} \leq k\)A1
since \(0 < \lambda < \frac{1}{2},\ k > 1\)A1 (3) (9)
# Question 5:

## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $mu + km\lambda u = kmv$ | M1 A1 | Conservation of momentum |
| $\frac{u}{k}(1 + k\lambda) = v$ | | |
| $v = e(u - \lambda u) = eu(1-\lambda)$ | M1 A1 | Newton's law of restitution |
| $\Rightarrow \frac{u}{k}(1+k\lambda) = eu(1-\lambda)$ | M1 | |
| $\Rightarrow \dfrac{(1+k\lambda)}{k(1-\lambda)} = e$ | A1 | (6) |

## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\dfrac{1+k\lambda}{k(1-\lambda)} \leq 1 \Rightarrow 1 + k\lambda \leq k(1-\lambda)$ | M1 | |
| $\Rightarrow \dfrac{1}{1-2\lambda} \leq k$ | A1 | |
| since $0 < \lambda < \frac{1}{2},\ k > 1$ | A1 | (3) **(9)** |

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5. A smooth sphere $S$ of mass $m$ is moving with speed $u$ on a smooth horizontal plane. The sphere $S$ collides with another smooth sphere $T$, of equal radius to $S$ but of mass $k m$, moving in the same straight line and in the same direction with speed $\lambda u , 0 < \lambda < \frac { 1 } { 2 }$. The coefficient of restitution between $S$ and $T$ is $e$.

Given that $S$ is brought to rest by the impact,
\begin{enumerate}[label=(\alph*)]
\item show that $e = \frac { 1 + k \lambda } { k ( 1 - \lambda ) }$.
\item Deduce that $k > 1$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2  Q5 [9]}}