Edexcel M2 — Question 4 9 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPower and driving force
TypeVariable resistance: find k or constants
DifficultyStandard +0.3 This is a standard M2 work-energy question requiring force equilibrium at constant speed (resolving forces parallel to slope) and power calculation. The steps are routine: equate component of weight to resistance to find k, then apply P=Fv with resistance plus weight component. Slightly easier than average due to straightforward setup and clear numerical values.
Spec6.02k Power: rate of doing work6.02l Power and velocity: P = Fv6.06a Variable force: dv/dt or v*dv/dx methods

4. The resistance to the motion of a cyclist is modelled as \(k v ^ { 2 } \mathrm {~N}\), where \(k\) is a constant and \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) is the speed of the cyclist. The total mass of the cyclist and his bicycle is 100 kg . The cyclist freewheels down a slope inclined at an angle \(\alpha\) to the horizontal, where \(\sin \alpha = \frac { 1 } { 20 }\), at a constant speed of \(3.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  1. Show that \(k = 4\). The cyclist ascends a slope inclined at an angle \(\beta\) to the horizontal, where \(\sin \beta = \frac { 1 } { 40 }\), at a constant speed of \(2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  2. Find the rate at which the cyclist is working.
    (6 marks)

Question 4:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(R(\checkmark),\ 100g \times \frac{1}{20} = k \times \left(\frac{7}{2}\right)^2\)M1 A1 Resolving along slope with correct terms
\(\Rightarrow k = 4\)A1 (3)
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(R(\nearrow),\ F - 100g \times \frac{1}{40} - 16 = 0\)M1 A2
\(\Rightarrow F = 40.5\ \text{N}\)A1
\(P = 40.5 \times 2\)M1
\(= 81\ \text{W}\)A1 (6) (9)
# Question 4:

## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $R(\checkmark),\ 100g \times \frac{1}{20} = k \times \left(\frac{7}{2}\right)^2$ | M1 A1 | Resolving along slope with correct terms |
| $\Rightarrow k = 4$ | A1 | (3) |

## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $R(\nearrow),\ F - 100g \times \frac{1}{40} - 16 = 0$ | M1 A2 | |
| $\Rightarrow F = 40.5\ \text{N}$ | A1 | |
| $P = 40.5 \times 2$ | M1 | |
| $= 81\ \text{W}$ | A1 | (6) **(9)** |

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4. The resistance to the motion of a cyclist is modelled as $k v ^ { 2 } \mathrm {~N}$, where $k$ is a constant and $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$ is the speed of the cyclist. The total mass of the cyclist and his bicycle is 100 kg . The cyclist freewheels down a slope inclined at an angle $\alpha$ to the horizontal, where $\sin \alpha = \frac { 1 } { 20 }$, at a constant speed of $3.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item Show that $k = 4$.

The cyclist ascends a slope inclined at an angle $\beta$ to the horizontal, where $\sin \beta = \frac { 1 } { 40 }$, at a constant speed of $2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\item Find the rate at which the cyclist is working.\\
(6 marks)
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2  Q4 [9]}}