Edexcel M2 2013 June — Question 5 13 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2013
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeRod hinged to wall with string support
DifficultyStandard +0.3 This is a standard M2 moments question requiring taking moments about the hinge, resolving forces horizontally and vertically, and using a geometric condition. The setup is straightforward with clearly defined forces, and part (a) guides students through the key step. The multi-part structure is typical but each part follows logically from the previous one with no novel insight required.
Spec3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force

5. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{cf960066-46b8-42a3-8a8b-d8deb76e7c70-09_522_997_276_477} \captionsetup{labelformat=empty} \caption{Figure 3}
\end{figure} A uniform rod \(A B\), of mass \(m\) and length \(2 a\), is freely hinged to a fixed point \(A\). A particle of mass \(m\) is attached to the rod at \(B\). The rod is held in equilibrium at an angle \(\theta\) to the horizontal by a force of magnitude \(F\) acting at the point \(C\) on the rod, where \(A C = b\), as shown in Figure 3. The force at \(C\) acts at right angles to \(A B\) and in the vertical plane containing \(A B\).
  1. Show that \(F = \frac { 3 a m g \cos \theta } { b }\).
  2. Find, in terms of \(a , b , g , m\) and \(\theta\),
    1. the horizontal component of the force acting on the rod at \(A\),
    2. the vertical component of the force acting on the rod at \(A\). Given that the force acting on the rod at \(A\) acts along the rod,
  3. find the value of \(\frac { a } { b }\).

5.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{cf960066-46b8-42a3-8a8b-d8deb76e7c70-09_522_997_276_477}
\captionsetup{labelformat=empty}
\caption{Figure 3}
\end{center}
\end{figure}

A uniform rod $A B$, of mass $m$ and length $2 a$, is freely hinged to a fixed point $A$. A particle of mass $m$ is attached to the rod at $B$. The rod is held in equilibrium at an angle $\theta$ to the horizontal by a force of magnitude $F$ acting at the point $C$ on the rod, where $A C = b$, as shown in Figure 3. The force at $C$ acts at right angles to $A B$ and in the vertical plane containing $A B$.
\begin{enumerate}[label=(\alph*)]
\item Show that $F = \frac { 3 a m g \cos \theta } { b }$.
\item Find, in terms of $a , b , g , m$ and $\theta$,
\begin{enumerate}[label=(\roman*)]
\item the horizontal component of the force acting on the rod at $A$,
\item the vertical component of the force acting on the rod at $A$.

Given that the force acting on the rod at $A$ acts along the rod,
\end{enumerate}\item find the value of $\frac { a } { b }$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2013 Q5 [13]}}