| Exam Board | Edexcel |
|---|---|
| Module | M2 (Mechanics 2) |
| Year | 2013 |
| Session | June |
| Marks | 5 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Impulse and momentum (advanced) |
| Type | Velocity after impulse (direct calculation) |
| Difficulty | Moderate -0.8 This is a straightforward application of the impulse-momentum theorem with vector components. Students need to apply Impulse = change in momentum, add vectors component-wise, then find the magnitude. It's a standard M2 textbook exercise requiring only direct formula application with no problem-solving insight or geometric complexity. |
| Spec | 1.10c Magnitude and direction: of vectors6.03e Impulse: by a force6.03f Impulse-momentum: relation |
| Answer | Marks | Guidance |
|---|---|---|
| 1 | 1 | 2 |
| 1/2 | 1/2 | y |
| AOB | OBCD | DOE |
| 1 | 2 | 1 |
| 1 | 1 | 1 |
Question 1:
| | |
|---|---|---|
| 1 | 1 | 2 |
| 1/2 | 1/2 | y |
AOB | OBCD | DOE | whole
1 | 2 | 1 | 4
1 | 1 | 1 | 1 | 4\begin{enumerate}
\item A particle $P$ of mass 2 kg is moving with velocity $( \mathbf { i } - 4 \mathbf { j } ) \mathrm { m } \mathrm { s } ^ { - 1 }$ when it receives an impulse of $( 3 \mathbf { i } + 6 \mathbf { j } ) \mathrm { N } \mathrm { s }$.
\end{enumerate}
Find the speed of $P$ immediately after the impulse is applied.\\
(5)\\
\hfill \mbox{\textit{Edexcel M2 2013 Q1 [5]}}