CAIE P2 2012 June — Question 4 8 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2012
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeExpress and solve equation
DifficultyStandard +0.3 This is a standard harmonic form question with routine steps: finding R and α using Pythagorean theorem and inverse tan, solving a transformed equation, and identifying the maximum value. All techniques are textbook exercises requiring no novel insight, making it slightly easier than average.
Spec1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

4
  1. Express \(9 \sin \theta - 12 \cos \theta\) in the form \(R \sin ( \theta - \alpha )\), where \(R > 0\) and \(0 ^ { \circ } < \alpha < 90 ^ { \circ }\). Give the value of \(\alpha\) correct to 2 decimal places. Hence
  2. solve the equation \(9 \sin \theta - 12 \cos \theta = 4\) for \(0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }\),
  3. state the largest value of \(k\) for which the equation \(9 \sin \theta - 12 \cos \theta = k\) has any solutions.

AnswerMarks Guidance
(i) State or imply \(R = 15\)B1
Use appropriate formula to find \(a\)M1
Obtain \(53.13°\)A1 [3]
(ii) Attempt to find at least one value of \(\theta - a\)M1
Obtain one correct value \(68.6°\) of \(\theta\)A1
Carry out correct method to find second answerM1
Obtain \(217.7°\) and no others in rangeA1 [4]
(iii) State \(15\), following their value of \(R\) from part (i)B1✓ [1]
**(i)** State or imply $R = 15$ | B1 |
Use appropriate formula to find $a$ | M1 |
Obtain $53.13°$ | A1 | [3]

**(ii)** Attempt to find at least one value of $\theta - a$ | M1 |
Obtain one correct value $68.6°$ of $\theta$ | A1 |
Carry out correct method to find second answer | M1 |
Obtain $217.7°$ and no others in range | A1 | [4]

**(iii)** State $15$, following their value of $R$ from part (i) | B1✓ | [1]

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4 (i) Express $9 \sin \theta - 12 \cos \theta$ in the form $R \sin ( \theta - \alpha )$, where $R > 0$ and $0 ^ { \circ } < \alpha < 90 ^ { \circ }$. Give the value of $\alpha$ correct to 2 decimal places.

Hence\\
(ii) solve the equation $9 \sin \theta - 12 \cos \theta = 4$ for $0 ^ { \circ } \leqslant \theta \leqslant 360 ^ { \circ }$,\\
(iii) state the largest value of $k$ for which the equation $9 \sin \theta - 12 \cos \theta = k$ has any solutions.

\hfill \mbox{\textit{CAIE P2 2012 Q4 [8]}}