CAIE P2 2012 June — Question 7 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2012
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeIntegrate using double angle
DifficultyStandard +0.3 This is a straightforward two-part question requiring expansion of a squared trigonometric expression, application of double angle formulae (standard identities), and then direct integration. The 'show that' structure guides students through the algebraic manipulation, and the integration is routine once the double angle form is established. Slightly above average due to the multi-step nature and need to recognize double angle identities, but well within standard P2/C3 expectations.
Spec1.05l Double angle formulae: and compound angle formulae1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

7
  1. Show that \(( 2 \sin x + \cos x ) ^ { 2 }\) can be written in the form \(\frac { 5 } { 2 } + 2 \sin 2 x - \frac { 3 } { 2 } \cos 2 x\).
  2. Hence find the exact value of \(\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } ( 2 \sin x + \cos x ) ^ { 2 } \mathrm {~d} x\).

AnswerMarks Guidance
(i) Expand to obtain 4 \(\sin^2 x + 4 \sin x \cos x + \cos^2 x\)B1
Use 2 \(\sin x \cos x = \sin 2x\)B1
Attempt to express \(\sin^2 x\) or \(\cos^2 x\) (or both) in terms of \(\cos 2x\)M1
Obtain correct \(\frac{1}{2}k(1 - \cos 2x)\) for their \(k \sin^2 x\) or equivalentA1∨
Confirm given answer \(\frac{5}{2} + 2 \sin 2x - \frac{3}{2} \cos 2x\)A1 [5]
(ii) Integrate to obtain form \(px + q \cos 2x + r \sin 2x\)M1
Obtain \(\frac{5}{2}x - \cos 2x - \frac{3}{4} \sin 2x\)A1
Substitute limits in integral of form \(px + q \cos 2x + r \sin 2x\) and attempt simplificationDM1
Obtain \(\frac{5}{8}\pi + \frac{1}{4}\) or exact equivalentA1 [4]
**(i)** Expand to obtain 4 $\sin^2 x + 4 \sin x \cos x + \cos^2 x$ | B1 |
Use 2 $\sin x \cos x = \sin 2x$ | B1 |
Attempt to express $\sin^2 x$ or $\cos^2 x$ (or both) in terms of $\cos 2x$ | M1 |
Obtain correct $\frac{1}{2}k(1 - \cos 2x)$ for their $k \sin^2 x$ or equivalent | A1∨ |
Confirm given answer $\frac{5}{2} + 2 \sin 2x - \frac{3}{2} \cos 2x$ | A1 | [5]

**(ii)** Integrate to obtain form $px + q \cos 2x + r \sin 2x$ | M1 |
Obtain $\frac{5}{2}x - \cos 2x - \frac{3}{4} \sin 2x$ | A1 |
Substitute limits in integral of form $px + q \cos 2x + r \sin 2x$ and attempt simplification | DM1 |
Obtain $\frac{5}{8}\pi + \frac{1}{4}$ or exact equivalent | A1 | [4]
7 (i) Show that $( 2 \sin x + \cos x ) ^ { 2 }$ can be written in the form $\frac { 5 } { 2 } + 2 \sin 2 x - \frac { 3 } { 2 } \cos 2 x$.\\
(ii) Hence find the exact value of $\int _ { 0 } ^ { \frac { 1 } { 4 } \pi } ( 2 \sin x + \cos x ) ^ { 2 } \mathrm {~d} x$.

\hfill \mbox{\textit{CAIE P2 2012 Q7 [9]}}