CAIE P2 2012 June — Question 6 9 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2012
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
TypeIterative method for parameter value
DifficultyStandard +0.8 This question requires finding dy/dx using the chain rule for parametric equations, algebraic manipulation to derive the iterative formula, then careful execution of the iteration process. While the calculus is standard A-level, the algebraic rearrangement to isolate the iterative form and the numerical method application make this moderately challenging, requiring multiple techniques and precision.
Spec1.07s Parametric and implicit differentiation1.09c Simple iterative methods: x_{n+1} = g(x_n), cobweb and staircase diagrams

6 A curve has parametric equations $$x = \frac { 1 } { ( 2 t + 1 ) ^ { 2 } } , \quad y = \sqrt { } ( t + 2 )$$ The point \(P\) on the curve has parameter \(p\) and it is given that the gradient of the curve at \(P\) is - 1 .
  1. Show that \(p = ( p + 2 ) ^ { \frac { 1 } { 6 } } - \frac { 1 } { 2 }\).
  2. Use an iterative process based on the equation in part (i) to find the value of \(p\) correct to 3 decimal places. Use a starting value of 0.7 and show the result of each iteration to 5 decimal places.

AnswerMarks Guidance
(i) Obtain derivative of form \(k(2t + 1)^{-3}\)M1
Obtain \(-4(2t + 1)^{-3}\) or equivalent as derivative of \(x\)A1
Obtain \(\frac{1}{2}(t + 2)^{-\frac{1}{2}}\) or equivalent as derivative of \(y\)B1
Equate attempt at \(\frac{dy}{dx}\) to \(-1\)M1
Obtain \((2p + 1)^3 = 8(p + 2)^2\) or equivalentA1
Confirm given answer \(p = (p + 2)^2 - \frac{3}{4}\)A1 [6]
(ii) Use iteration process correctly at least onceM1
Obtain final answer 0.678A1
Show sufficient iterations to 5 decimal places to justify answer or show a sign change in the interval \((0.6775, 0.6785)\)A1 [3]
\([0.7 \to 0.68003 \to 0.67857 \to 0.67847 \to 0.67846]\)
**(i)** Obtain derivative of form $k(2t + 1)^{-3}$ | M1 |
Obtain $-4(2t + 1)^{-3}$ or equivalent as derivative of $x$ | A1 |
Obtain $\frac{1}{2}(t + 2)^{-\frac{1}{2}}$ or equivalent as derivative of $y$ | B1 |
Equate attempt at $\frac{dy}{dx}$ to $-1$ | M1 |
Obtain $(2p + 1)^3 = 8(p + 2)^2$ or equivalent | A1 |
Confirm given answer $p = (p + 2)^2 - \frac{3}{4}$ | A1 | [6]

**(ii)** Use iteration process correctly at least once | M1 |
Obtain final answer 0.678 | A1 |
Show sufficient iterations to 5 decimal places to justify answer or show a sign change in the interval $(0.6775, 0.6785)$ | A1 | [3]
$[0.7 \to 0.68003 \to 0.67857 \to 0.67847 \to 0.67846]$
6 A curve has parametric equations

$$x = \frac { 1 } { ( 2 t + 1 ) ^ { 2 } } , \quad y = \sqrt { } ( t + 2 )$$

The point $P$ on the curve has parameter $p$ and it is given that the gradient of the curve at $P$ is - 1 .\\
(i) Show that $p = ( p + 2 ) ^ { \frac { 1 } { 6 } } - \frac { 1 } { 2 }$.\\
(ii) Use an iterative process based on the equation in part (i) to find the value of $p$ correct to 3 decimal places. Use a starting value of 0.7 and show the result of each iteration to 5 decimal places.

\hfill \mbox{\textit{CAIE P2 2012 Q6 [9]}}