Edexcel M2 2008 June — Question 2 9 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2008
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions 1
TypeDirect collision with speed relationships
DifficultyStandard +0.3 This is a standard M2 collision problem requiring conservation of momentum and Newton's restitution law. Part (a) involves straightforward algebraic manipulation to show a given result, and part (b) requires calculating kinetic energies before and after—both are routine applications of well-practiced formulas with no novel insight needed. Slightly easier than average due to the 'show that' structure guiding students to the answer.
Spec6.03b Conservation of momentum: 1D two particles6.03j Perfectly elastic/inelastic: collisions6.03k Newton's experimental law: direct impact6.03l Newton's law: oblique impacts

2. A particle \(A\) of mass \(4 m\) is moving with speed \(3 u\) in a straight line on a smooth horizontal table. The particle \(A\) collides directly with a particle \(B\) of mass \(3 m\) moving with speed \(2 u\) in the same direction as \(A\). The coefficient of restitution between \(A\) and \(B\) is \(e\). Immediately after the collision the speed of \(B\) is \(4 e u\).
  1. Show that \(e = \frac { 3 } { 4 }\).
  2. Find the total kinetic energy lost in the collision.

Part (a):
AnswerMarks Guidance
LM NEL: \(12mu + 6mu = 4mx + 12meu\)B1 M1 A1
\(4eu - x = eu\)
Eliminating \(x\) to obtain equation in \(e\)DM1
Leading to \(e = \frac{3}{4}\) ★A1 cso [5]
Part (b):
AnswerMarks Guidance
\(x = 3eu\) or \(\frac{9}{4}u\) or \(4.5u - 3eu\)B1 seen or implied in (b)
M1 A1 ft
Loss in KE \(= \frac{1}{2}4m(3u)^2 + \frac{1}{2}3m(2u)^2 - \frac{1}{2}4m\left(\frac{9}{4}u\right)^2 - \frac{1}{2}3m(3u)^2\) fit their \(x\)
\(= 24mu^2 - 23\frac{5}{8}mu^2 - \frac{3}{8}mu^2 = 0.375mu^2\)A1 [4] [9]
**Part (a):**
LM NEL: $12mu + 6mu = 4mx + 12meu$ | B1 M1 A1 |
$4eu - x = eu$ | |
Eliminating $x$ to obtain equation in $e$ | DM1 |
Leading to $e = \frac{3}{4}$ ★ | A1 cso | [5]

**Part (b):**
$x = 3eu$ or $\frac{9}{4}u$ or $4.5u - 3eu$ | B1 | seen or implied in (b)
| M1 A1 ft |
Loss in KE $= \frac{1}{2}4m(3u)^2 + \frac{1}{2}3m(2u)^2 - \frac{1}{2}4m\left(\frac{9}{4}u\right)^2 - \frac{1}{2}3m(3u)^2$ | | fit their $x$
$= 24mu^2 - 23\frac{5}{8}mu^2 - \frac{3}{8}mu^2 = 0.375mu^2$ | A1 | [4] [9]
2. A particle $A$ of mass $4 m$ is moving with speed $3 u$ in a straight line on a smooth horizontal table. The particle $A$ collides directly with a particle $B$ of mass $3 m$ moving with speed $2 u$ in the same direction as $A$. The coefficient of restitution between $A$ and $B$ is $e$. Immediately after the collision the speed of $B$ is $4 e u$.
\begin{enumerate}[label=(\alph*)]
\item Show that $e = \frac { 3 } { 4 }$.
\item Find the total kinetic energy lost in the collision.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2008 Q2 [9]}}