OCR MEI M1 — Question 6 5 marks

Exam BoardOCR MEI
ModuleM1 (Mechanics 1)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicForces, equilibrium and resultants
TypeEquilibrium of particle under coplanar forces
DifficultyModerate -0.8 This is a straightforward equilibrium problem requiring resolution of forces in two perpendicular directions. Students need to apply basic trigonometry and solve two simultaneous equations, which is a standard M1 technique with no novel problem-solving required. The question is slightly easier than average due to its routine nature and clear structure.
Spec3.03m Equilibrium: sum of resolved forces = 0

6 Fig. 1 shows four forces in equilibrium. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{82f933a6-c17e-4b41-ae2b-3cc9d0ba975c-4_364_328_1748_901} \captionsetup{labelformat=empty} \caption{Fig. 1}
\end{figure}
  1. Find the value of \(P\).
  2. Hence find the value of \(Q\).

Question 6:
Part (i):
AnswerMarks Guidance
AnswerMark Guidance
\(\rightarrow\quad 40 - P\cos60 = 0\)M1 For any resolution in an equation involving \(P\). Allow for \(P = 40\cos60\) or \(P = 40\cos30\) or \(P = 40\sin60\) or \(P = 40\sin30\)
A1Correct equation
\(P = 80\)A1 cao
Total: 3
Part (ii):
AnswerMarks Guidance
AnswerMark Guidance
\(\downarrow\quad Q + P\cos30 = 120\)M1 Resolve vert. All forces present. Allow \(\sin \leftrightarrow \cos\). No extra forces. Allow wrong signs
\(Q = 40(3 - \sqrt{3}) = 50.7179\ldots\) so \(50.7\) (3 s.f.)A1 cao
Total: 2
## Question 6:

**Part (i):**

| Answer | Mark | Guidance |
|--------|------|----------|
| $\rightarrow\quad 40 - P\cos60 = 0$ | M1 | For any resolution in an equation involving $P$. Allow for $P = 40\cos60$ or $P = 40\cos30$ or $P = 40\sin60$ or $P = 40\sin30$ |
| | A1 | Correct equation |
| $P = 80$ | A1 | cao |
| **Total: 3** | | |

**Part (ii):**

| Answer | Mark | Guidance |
|--------|------|----------|
| $\downarrow\quad Q + P\cos30 = 120$ | M1 | Resolve vert. All forces present. Allow $\sin \leftrightarrow \cos$. No extra forces. Allow wrong signs |
| $Q = 40(3 - \sqrt{3}) = 50.7179\ldots$ so $50.7$ (3 s.f.) | A1 | cao |
| **Total: 2** | | |

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6 Fig. 1 shows four forces in equilibrium.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{82f933a6-c17e-4b41-ae2b-3cc9d0ba975c-4_364_328_1748_901}
\captionsetup{labelformat=empty}
\caption{Fig. 1}
\end{center}
\end{figure}

(i) Find the value of $P$.\\
(ii) Hence find the value of $Q$.

\hfill \mbox{\textit{OCR MEI M1  Q6 [5]}}