OCR MEI M1 — Question 4 5 marks

Exam BoardOCR MEI
ModuleM1 (Mechanics 1)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeFind acceleration from distances/times
DifficultyStandard +0.3 This is a straightforward SUVAT problem requiring application of standard kinematic equations with given values. Part (i) uses s=ut+½at² directly, and part (ii) uses v²=u²+2as then v=u+at. All values are provided clearly, requiring only systematic substitution and algebraic manipulation without conceptual challenges or novel problem-solving.
Spec3.02d Constant acceleration: SUVAT formulae

4 Fig. 4 illustrates points \(A , B\) and \(C\) on a straight race track. The distance \(A B\) is 300 m and \(A C\) is 500 m .
A car is travelling along the track with uniform acceleration. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{82f933a6-c17e-4b41-ae2b-3cc9d0ba975c-4_70_1329_397_352} \captionsetup{labelformat=empty} \caption{Fig. 4}
\end{figure} Initially the car is at A and travelling in the direction AB with speed \(5 \mathrm {~ms} ^ { - 1 }\). After 20 s it is at C .
  1. Find the acceleration of the car.
  2. Find the speed of the car at B and how long it takes to travel from A to B .

Question 4:
Part (i):
AnswerMarks Guidance
AnswerMark Guidance
Any one force in correct direction correctly labelled with arrow or all forces with correct directions and arrowsB1 A force may be replaced by its components if labelled correctly e.g. \(mg\cos20°\), \(mg\sin20°\)
All correct (Accept words for labels and weight as \(W\), \(mg\), 147 (N)) No extra or duplicate forcesB1 Do not allow force and its components unless components are clearly distinguished, e.g. by broken lines
Total: 2
Part (ii) — Either (Up the plane):
AnswerMarks Guidance
AnswerMark Guidance
\(P\cos20 - 15 \times 9.8 \times \sin20 = 0\)M1 Attempt to resolve at least one force up plane. Accept mass not weight. No extra forces. If other directions used, all forces must be present but see below for resolving vertically and horizontally
A1Accept only error as consistent \(s \leftrightarrow c\)
\(P = 53.50362\ldots\) so \(53.5\) (3 s.f.)A1 cao
Total: 3
Or (Vertically and horizontally):
AnswerMarks Guidance
AnswerMark Guidance
\(R\cos20° = 15g\), \(R\sin20° = P\), Eliminate \(R\)M1 Attempt to resolve all forces both horizontally and vertically and attempt to combine into a single equation. No extra forces. Accept \(s \leftrightarrow c\). Accept mass not weight
\(P = \dfrac{15g}{\cos20°} \times \sin20°\)A1 Accept only error as consistent \(s \leftrightarrow c\)
\(P = 53.5\) (3 s.f.)A1 cao
Total: 3
Or (Triangle of forces):
AnswerMarks Guidance
AnswerMark Guidance
Triangle drawn and labelledM1 All sides must be labelled and in correct orientation; three forces only; condone no arrows
\(\dfrac{P}{15g} = \tan20°\)A1 Oe
\(P = 53.5\) (3 s.f.)A1 cao
Total: 3
## Question 4:

**Part (i):**

| Answer | Mark | Guidance |
|--------|------|----------|
| Any one force in correct direction correctly labelled with arrow **or** all forces with correct directions and arrows | B1 | A force may be replaced by its components if labelled correctly e.g. $mg\cos20°$, $mg\sin20°$ |
| All correct (Accept words for labels and weight as $W$, $mg$, 147 (N)) No extra or duplicate forces | B1 | Do not allow force **and** its components unless components are clearly distinguished, e.g. by broken lines |
| **Total: 2** | | |

**Part (ii) — Either (Up the plane):**

| Answer | Mark | Guidance |
|--------|------|----------|
| $P\cos20 - 15 \times 9.8 \times \sin20 = 0$ | M1 | Attempt to resolve at least one force up plane. Accept mass not weight. No extra forces. If other directions used, all forces must be present but see below for resolving vertically and horizontally |
| | A1 | Accept only error as consistent $s \leftrightarrow c$ |
| $P = 53.50362\ldots$ so $53.5$ (3 s.f.) | A1 | cao |
| **Total: 3** | | |

**Or (Vertically and horizontally):**

| Answer | Mark | Guidance |
|--------|------|----------|
| $R\cos20° = 15g$, $R\sin20° = P$, Eliminate $R$ | M1 | Attempt to resolve all forces both horizontally and vertically and attempt to combine into a single equation. No extra forces. Accept $s \leftrightarrow c$. Accept mass not weight |
| $P = \dfrac{15g}{\cos20°} \times \sin20°$ | A1 | Accept only error as consistent $s \leftrightarrow c$ |
| $P = 53.5$ (3 s.f.) | A1 | cao |
| **Total: 3** | | |

**Or (Triangle of forces):**

| Answer | Mark | Guidance |
|--------|------|----------|
| Triangle drawn and labelled | M1 | All sides must be labelled and in correct orientation; three forces only; condone no arrows |
| $\dfrac{P}{15g} = \tan20°$ | A1 | Oe |
| $P = 53.5$ (3 s.f.) | A1 | cao |
| **Total: 3** | | |

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4 Fig. 4 illustrates points $A , B$ and $C$ on a straight race track. The distance $A B$ is 300 m and $A C$ is 500 m .\\
A car is travelling along the track with uniform acceleration.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{82f933a6-c17e-4b41-ae2b-3cc9d0ba975c-4_70_1329_397_352}
\captionsetup{labelformat=empty}
\caption{Fig. 4}
\end{center}
\end{figure}

Initially the car is at A and travelling in the direction AB with speed $5 \mathrm {~ms} ^ { - 1 }$. After 20 s it is at C .\\
(i) Find the acceleration of the car.\\
(ii) Find the speed of the car at B and how long it takes to travel from A to B .

\hfill \mbox{\textit{OCR MEI M1  Q4 [5]}}