Moderate -0.3 This is a straightforward application of the quotient rule to find a derivative, followed by standard tangent line procedure (evaluate f(-2), find f'(-2), use point-slope form). Slightly easier than average because it's a single-part question with routine algebraic manipulation and no conceptual challenges beyond applying a standard technique.
1.
$$f ( x ) = \frac { 4 x - 1 } { 2 x + 1 }$$
Find an equation for the tangent to the curve \(y = \mathrm { f } ( x )\) at the point where \(x = - 2\), giving your answer in the form \(a x + b y + c = 0\), where \(a , b\) and \(c\) are integers.
1.
$$f ( x ) = \frac { 4 x - 1 } { 2 x + 1 }$$
Find an equation for the tangent to the curve $y = \mathrm { f } ( x )$ at the point where $x = - 2$, giving your answer in the form $a x + b y + c = 0$, where $a , b$ and $c$ are integers.\\
\hfill \mbox{\textit{OCR C3 Q1 [5]}}