CAIE P2 2010 June — Question 5 7 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2010
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiating Transcendental Functions
TypeShow stationary point exists or gradient has specific property
DifficultyModerate -0.8 This is a straightforward application of the product rule for differentiation. Part (i) requires finding dy/dx = x²e^(-x)(3-x) and verifying it equals zero at x=3 (simple substitution). Part (ii) requires finding the gradient and y-coordinate at x=1, then using y-y₁=m(x-x₁). Both parts are routine textbook exercises with no problem-solving insight required, making this easier than average.
Spec1.07m Tangents and normals: gradient and equations1.07n Stationary points: find maxima, minima using derivatives1.07q Product and quotient rules: differentiation

5 The equation of a curve is \(y = x ^ { 3 } \mathrm { e } ^ { - x }\).
  1. Show that the curve has a stationary point where \(x = 3\).
  2. Find the equation of the tangent to the curve at the point where \(x = 1\).

AnswerMarks Guidance
(i) Use product ruleM1
Obtain correct derivative in any formA1
Show that derivative is equal to zero when \(x = 3\)A1 [3]
(ii) Substitute \(x = 1\) into gradient function, obtaining \(2e^{-1}\) or equivalentM1
State or imply required \(y\)-coordinate is \(e^{-1}\)B1
Form equation of line through \((1, e^{-1})\) with gradient found (NOT the normal)M1
Obtain equation in any correct formA1 [4]
**(i)** Use product rule | M1 |

Obtain correct derivative in any form | A1 |

Show that derivative is equal to zero when $x = 3$ | A1 | [3]

**(ii)** Substitute $x = 1$ into gradient function, obtaining $2e^{-1}$ or equivalent | M1 |

State or imply required $y$-coordinate is $e^{-1}$ | B1 |

Form equation of line through $(1, e^{-1})$ with gradient found (NOT the normal) | M1 |

Obtain equation in any correct form | A1 | [4]
5 The equation of a curve is $y = x ^ { 3 } \mathrm { e } ^ { - x }$.\\
(i) Show that the curve has a stationary point where $x = 3$.\\
(ii) Find the equation of the tangent to the curve at the point where $x = 1$.\\

\hfill \mbox{\textit{CAIE P2 2010 Q5 [7]}}