OCR MEI C2 — Question 5 5 marks

Exam BoardOCR MEI
ModuleC2 (Core Mathematics 2)
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDifferentiation from First Principles
TypeChord gradient estimation
DifficultyEasy -1.2 This is a straightforward application of chord gradient formula with clear instructions. Part (i) appears to have a typo (both x-values are 4), making it trivial or impossible. Part (ii) is routine: choose a closer point and apply the same formula. No conceptual difficulty beyond basic substitution and arithmetic—well below average A-level challenge.
Spec1.07a Derivative as gradient: of tangent to curve

5 The equation of a curve is \(y = \sqrt { 1 + 2 x }\).
  1. Calculate the gradient of the chord joining the points on the curve where \(x = 4\) and \(x = 4\). Give your answer correct to 4 decimal places.
  2. Showing the points you use, calculate the gradient of another chord of the curve which is a closer approximation to the gradient of the curve when \(x = 4\). \begin{figure}[h]
    \includegraphics[alt={},max width=\textwidth]{f540b962-ee6b-409a-a2a1-cd7ad4945514-2_1031_1113_273_499} \captionsetup{labelformat=empty} \caption{Fig. 5}
    \end{figure} Fig. 5 shows the graph of \(y = 2 ^ { x }\).

Question 5(i):
AnswerMarks Guidance
ruled line touching curve at \(x = 2\)M1 intent to touch, but must not clearly cut curve
their \(\frac{y_2 - y_1}{x_2 - x_1}\) from their *tangent*M1 may be on graph or in working; must use correct points from their line; their tangent may be at another point; M0 for reciprocal
answer in range 2.5 to 3.0 inclusiveA1 both M1s must be awarded; (value is approx 2.773)
Question 5(ii):
AnswerMarks Guidance
3.482202253... and 4.59479342... rot to 3 or more sfB1
2.78 to 2.7815 or 2.8B1 mark the final answer; 2.781477917...
## Question 5(i):

ruled line touching curve at $x = 2$ | M1 | intent to touch, but must not clearly cut curve
their $\frac{y_2 - y_1}{x_2 - x_1}$ from their *tangent* | M1 | may be on graph or in working; must use correct points from their line; their tangent may be at another point; **M0** for reciprocal
answer in range 2.5 to 3.0 inclusive | A1 | both **M1**s must be awarded; (value is approx 2.773)

## Question 5(ii):

3.482202253... and 4.59479342... rot to 3 or more sf | B1 |
2.78 to 2.7815 or 2.8 | B1 | mark the final answer; 2.781477917...

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5 The equation of a curve is $y = \sqrt { 1 + 2 x }$.\\
(i) Calculate the gradient of the chord joining the points on the curve where $x = 4$ and $x = 4$. Give your answer correct to 4 decimal places.\\
(ii) Showing the points you use, calculate the gradient of another chord of the curve which is a closer approximation to the gradient of the curve when $x = 4$.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{f540b962-ee6b-409a-a2a1-cd7ad4945514-2_1031_1113_273_499}
\captionsetup{labelformat=empty}
\caption{Fig. 5}
\end{center}
\end{figure}

Fig. 5 shows the graph of $y = 2 ^ { x }$.\\

\hfill \mbox{\textit{OCR MEI C2  Q5 [5]}}