Easy -1.3 This is a straightforward application of the chord gradient formula (change in y over change in x) to estimate a derivative. It requires only basic arithmetic with no conceptual challenge beyond recognizing that chord gradient approximates the tangent gradient—a standard introductory exercise in differentiation.
3 The points \(\mathrm { P } ( 2,3.6 )\) and \(\mathrm { Q } ( 2.2,2.4 )\) lie on the curve \(y = \mathrm { f } ( x )\). Use P and Q to estimate the gradient of the curve at the point where \(x = 2\).
M1 may be embedded eg in equation of straight line
\(-6\) cao
A1
B2 if unsupported; ignore subsequent work irrelevant to finding the gradient
## Question 3:
$\frac{2.4 - 3.6}{2.2 - 2}$ oe | M1 | M1 may be embedded eg in equation of straight line
$-6$ cao | A1 | B2 if unsupported; ignore subsequent work irrelevant to finding the gradient
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3 The points $\mathrm { P } ( 2,3.6 )$ and $\mathrm { Q } ( 2.2,2.4 )$ lie on the curve $y = \mathrm { f } ( x )$. Use P and Q to estimate the gradient of the curve at the point where $x = 2$.
\hfill \mbox{\textit{OCR MEI C2 Q3 [2]}}