CAIE P2 2009 June — Question 3 4 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2009
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicIndefinite & Definite Integrals
TypeTrapezium rule estimation
DifficultyModerate -0.8 This is a straightforward application of the trapezium rule with only 2 intervals, requiring basic substitution into a formula and evaluation of a simple function at three points. Part (ii) tests understanding of concavity but is a standard textbook question requiring minimal insight. Significantly easier than average A-level questions.
Spec1.09f Trapezium rule: numerical integration

3 \includegraphics[max width=\textwidth, alt={}, center]{b9556031-871d-4dd3-9523-e3438a41339f-2_451_775_559_683} The diagram shows the curve \(y = \frac { 1 } { 1 + \sqrt { } x }\) for values of \(x\) from 0 to 2 .
  1. Use the trapezium rule with two intervals to estimate the value of $$\int _ { 0 } ^ { 2 } \frac { 1 } { 1 + \sqrt { } x } \mathrm {~d} x$$ giving your answer correct to 2 decimal places.
  2. State, with a reason, whether the trapezium rule gives an under-estimate or an over-estimate of the true value of the integral in part (i).

AnswerMarks Guidance
(i) Show or imply correct ordinates 1, 0.5, 0.414213 ...B1
Use correct formula, or equivalent, with \(h = 1\) and three ordinatesM1
Obtain answer 1.21 with no errors seenA1 [3]
(ii) Justify the statement that the rule gives an over-estimateB1 [1]
**(i)** Show or imply correct ordinates 1, 0.5, 0.414213 ... | B1 |

Use correct formula, or equivalent, with $h = 1$ and three ordinates | M1 |

Obtain answer 1.21 with no errors seen | A1 | [3]

**(ii)** Justify the statement that the rule gives an over-estimate | B1 | [1]
3\\
\includegraphics[max width=\textwidth, alt={}, center]{b9556031-871d-4dd3-9523-e3438a41339f-2_451_775_559_683}

The diagram shows the curve $y = \frac { 1 } { 1 + \sqrt { } x }$ for values of $x$ from 0 to 2 .\\
(i) Use the trapezium rule with two intervals to estimate the value of

$$\int _ { 0 } ^ { 2 } \frac { 1 } { 1 + \sqrt { } x } \mathrm {~d} x$$

giving your answer correct to 2 decimal places.\\
(ii) State, with a reason, whether the trapezium rule gives an under-estimate or an over-estimate of the true value of the integral in part (i).

\hfill \mbox{\textit{CAIE P2 2009 Q3 [4]}}