| Exam Board | OCR MEI |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2009 |
| Session | June |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Travel graphs |
| Type | Distance from velocity-time graph |
| Difficulty | Easy -1.2 This is a straightforward velocity-time graph question requiring only basic area calculations under straight-line segments. Part (i) is direct trapezium area, part (ii) requires simple equation solving with areas, and part (iii) combines results. All techniques are routine with no conceptual challenges beyond understanding that area represents distance. |
| Spec | 3.02b Kinematic graphs: displacement-time and velocity-time3.02c Interpret kinematic graphs: gradient and area |
1 The velocity-time graph shown in Fig. 1 represents the straight line motion of a toy car. All the lines on the graph are straight.
\begin{figure}[h]
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\includegraphics[alt={},max width=\textwidth]{d6e78f93-ac2c-4053-87e4-5e5537d6dc3d-2_579_1317_443_413}
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\caption{Fig. 1}
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The car starts at the point A at $t = 0$ and in the next 8 seconds moves to a point B .\\
(i) Find the distance from A to B .\\
$T$ seconds after leaving A, the car is at a point C which is a distance of 10 m from B .\\
(ii) Find the value of $T$.\\
(iii) Find the displacement from A to C .
\hfill \mbox{\textit{OCR MEI M1 2009 Q1 [6]}}