| Exam Board | OCR MEI |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2006 |
| Session | June |
| Marks | 8 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors Introduction & 2D |
| Type | Newton's second law with vector forces (find acceleration or force) |
| Difficulty | Moderate -0.8 This is a straightforward mechanics question testing basic vector operations (magnitude, direction, Newton's second law). Part (i) is simple Pythagoras, part (ii) requires vector subtraction and arctangent with bearing conversion, and part (iii) is direct application of F=ma followed by v=at. All are standard textbook exercises with no problem-solving insight required, making it easier than average. |
| Spec | 1.10c Magnitude and direction: of vectors3.03d Newton's second law: 2D vectors |
2 Force $\mathbf { F } _ { 1 }$ is $\binom { - 6 } { 13 } \mathrm {~N}$ and force $\mathbf { F } _ { 2 }$ is $\binom { - 3 } { 5 } \mathrm {~N}$, where $\binom { 1 } { 0 }$ and $\binom { 0 } { 1 }$ are vectors east and north respectively.\\
(i) Calculate the magnitude of $\mathbf { F } _ { 1 }$, correct to three significant figures.\\
(ii) Calculate the direction of the force $\mathbf { F } _ { 1 } - \mathbf { F } _ { 2 }$ as a bearing.
Force $\mathbf { F } _ { 2 }$ is the resultant of all the forces acting on an object of mass 5 kg .\\
(iii) Calculate the acceleration of the object and the change in its velocity after 10 seconds.
\hfill \mbox{\textit{OCR MEI M1 2006 Q2 [8]}}