OCR MEI M1 2006 June — Question 1 4 marks

Exam BoardOCR MEI
ModuleM1 (Mechanics 1)
Year2006
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSUVAT in 2D & Gravity
TypeVertical projection: max height
DifficultyModerate -0.8 This is a straightforward SUVAT application with vertical motion under gravity. Students need only apply standard equations (v = u + at for time to peak, then double it; s = ut + ½at² for height) with no problem-solving insight required. It's slightly easier than average due to being a direct two-step calculation with clearly stated conditions.
Spec3.02h Motion under gravity: vector form

1 A particle is thrown vertically upwards and returns to its point of projection after 6 seconds. Air resistance is negligible. Calculate the speed of projection of the particle and also the maximum height it reaches.

1 A particle is thrown vertically upwards and returns to its point of projection after 6 seconds. Air resistance is negligible.

Calculate the speed of projection of the particle and also the maximum height it reaches.

\hfill \mbox{\textit{OCR MEI M1 2006 Q1 [4]}}