| Exam Board | OCR |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2010 |
| Session | June |
| Marks | 9 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Momentum and Collisions |
| Type | Collision with two possible outcomes |
| Difficulty | Moderate -0.3 This is a straightforward momentum conservation problem with two scenarios. Part (i) requires a single application of conservation of momentum with clear direction. Part (ii) adds a simple kinematics step (distance = speed × time) after another momentum calculation. The question is slightly easier than average because it's a standard textbook exercise with no conceptual challenges—students just need to apply the momentum formula carefully with signs, which is routine M1 content. |
| Spec | 6.03b Conservation of momentum: 1D two particles |
2 Two particles $P$ and $Q$ are moving in opposite directions in the same straight line on a smooth horizontal surface when they collide. $P$ has mass 0.4 kg and speed $3 \mathrm {~m} \mathrm {~s} ^ { - 1 } . Q$ has mass 0.6 kg and speed $1.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. Immediately after the collision, the speed of $P$ is $0.1 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.\\
(i) Given that $P$ and $Q$ are moving in the same direction after the collision, find the speed of $Q$.\\
(ii) Given instead that $P$ and $Q$ are moving in opposite directions after the collision, find the distance between them 3 s after the collision.
\hfill \mbox{\textit{OCR M1 2010 Q2 [9]}}