| Exam Board | OCR |
|---|
| Module | C2 (Core Mathematics 2) |
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| Year | 2007 |
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| Session | June |
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| Topic | Trig Equations |
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5
- Show that the equation
$$3 \cos ^ { 2 } \theta = \sin \theta + 1$$
can be expressed in the form
$$3 \sin ^ { 2 } \theta + \sin \theta - 2 = 0$$
- Hence solve the equation
$$3 \cos ^ { 2 } \theta = \sin \theta + 1 ,$$
giving all values of \(\theta\) between \(0 ^ { \circ }\) and \(360 ^ { \circ }\).