OCR C2 2007 June — Question 3 5 marks

Exam BoardOCR
ModuleC2 (Core Mathematics 2)
Year2007
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicExponential Equations & Modelling
TypeSimple exponential equation solving
DifficultyModerate -0.8 This is a straightforward application of logarithms to solve an exponential equation—a standard C2 technique requiring only taking logs of both sides, applying log laws, and rearranging. The large exponent (200) doesn't add conceptual difficulty, just requires careful calculator work. Below average difficulty as it's purely procedural with no problem-solving element.
Spec1.06f Laws of logarithms: addition, subtraction, power rules1.06g Equations with exponentials: solve a^x = b

3 U se logarithms to solve the equation \(3 ^ { 2 x + 1 } = 5 ^ { 200 }\), giving the value of \(x\) correct to 3 significant figures.

\(\log_3(2^{+1}) = \log_5^{200}\)
\((2x+1)\log 3 = 200\log 5\)
\(2x + 1 = \frac{200\log 5}{\log 3}\)
AnswerMarks Guidance
\(x = 146\)M1, M1, A1, M1, A1 5 Introduce logarithms throughout. Drop power on at least one side. Obtain correct linear equation (now containing no powers). Attempt solution of linear equation. Obtain \(x = 146\), or better.
OR
\((2x+1) = \log_5 5^{200}\)
\(2x + 1 = 200\log_5 5\)
AnswerMarks
M1, M1, A1, M1, A1 5Introduce \(\log_5\) on right-hand side. Drop power of 200. Obtain correct equation. Attempt solution of linear equation. Obtain \(x = 146\), or better.
$\log_3(2^{+1}) = \log_5^{200}$

$(2x+1)\log 3 = 200\log 5$

$2x + 1 = \frac{200\log 5}{\log 3}$

$x = 146$ | M1, M1, A1, M1, A1 5 | Introduce logarithms throughout. Drop power on at least one side. Obtain correct linear equation (now containing no powers). Attempt solution of linear equation. Obtain $x = 146$, or better.

**OR**

$(2x+1) = \log_5 5^{200}$

$2x + 1 = 200\log_5 5$

| M1, M1, A1, M1, A1 5 | Introduce $\log_5$ on right-hand side. Drop power of 200. Obtain correct equation. Attempt solution of linear equation. Obtain $x = 146$, or better.
3 U se logarithms to solve the equation $3 ^ { 2 x + 1 } = 5 ^ { 200 }$, giving the value of $x$ correct to 3 significant figures.

\hfill \mbox{\textit{OCR C2 2007 Q3 [5]}}