OCR MEI C3 2005 June — Question 2 3 marks

Exam BoardOCR MEI
ModuleC3 (Core Mathematics 3)
Year2005
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicReciprocal Trig & Identities
TypeInverse trigonometric function equations
DifficultyEasy -1.2 This is a straightforward question requiring only direct evaluation of arcsin at a standard angle (π/6) and recall of the complementary relationship arcsin x + arccos x = π/2. No problem-solving or multi-step reasoning required—purely routine application of inverse trig definitions and a basic identity.
Spec1.05i Inverse trig functions: arcsin, arccos, arctan domains and graphs

2 Given that \(\arcsin x = \frac { 1 } { 6 } \pi\), find \(x\). Find \(\arccos x\) in terms of \(\pi\).

AnswerMarks Guidance
\(x = 1/2\) and \(\cos \theta = 1/2 \Rightarrow \theta = \pi/3\)B1, M1, A1 [3] M1A0 for 1.04... or 60°
$x = 1/2$ and $\cos \theta = 1/2 \Rightarrow \theta = \pi/3$ | B1, M1, A1 [3] | M1A0 for 1.04... or 60°
2 Given that $\arcsin x = \frac { 1 } { 6 } \pi$, find $x$. Find $\arccos x$ in terms of $\pi$.

\hfill \mbox{\textit{OCR MEI C3 2005 Q2 [3]}}