OCR MEI C3 2005 June — Question 3 3 marks

Exam BoardOCR MEI
ModuleC3 (Core Mathematics 3)
Year2005
SessionJune
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeFind composite function expression
DifficultyModerate -0.8 This is a straightforward composite function question requiring only the definition fg(x) = f(g(x)) = ln(x³) = 3ln(x) using log laws, followed by recognizing a simple vertical stretch transformation. Both parts are routine C3 exercises with minimal steps and no problem-solving required.
Spec1.02u Functions: definition and vocabulary (domain, range, mapping)1.02w Graph transformations: simple transformations of f(x)

3 The functions \(\mathrm { f } ( x )\) and \(\mathrm { g } ( x )\) are defined for the domain \(x > 0\) as follows: $$\mathrm { f } ( x ) = \ln x , \quad \mathrm {~g} ( x ) = x ^ { 3 } .$$ Express the composite function \(\mathrm { fg } ( x )\) in terms of \(\ln x\).
State the transformation which maps the curve \(y = \mathrm { f } ( x )\) onto the curve \(y = \mathrm { fg } ( x )\).

AnswerMarks Guidance
\(f(g(x)) = \ln(x^3) = 3\ln x\) with Stretch s.f. 3 in y directionM1, A1, B1 [3] \(\ln(x^3) = 3\ln x\)
$f(g(x)) = \ln(x^3) = 3\ln x$ with Stretch s.f. 3 in y direction | M1, A1, B1 [3] | $\ln(x^3) = 3\ln x$
3 The functions $\mathrm { f } ( x )$ and $\mathrm { g } ( x )$ are defined for the domain $x > 0$ as follows:

$$\mathrm { f } ( x ) = \ln x , \quad \mathrm {~g} ( x ) = x ^ { 3 } .$$

Express the composite function $\mathrm { fg } ( x )$ in terms of $\ln x$.\\
State the transformation which maps the curve $y = \mathrm { f } ( x )$ onto the curve $y = \mathrm { fg } ( x )$.

\hfill \mbox{\textit{OCR MEI C3 2005 Q3 [3]}}