OCR S3 Specimen — Question 2 7 marks

Exam BoardOCR
ModuleS3 (Statistics 3)
SessionSpecimen
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicDiscrete Random Variables
TypeMass and measurement problems
DifficultyStandard +0.3 This is a straightforward application of properties of linear combinations of random variables (variance of sums/differences). While it requires identifying that match mass = (full box - empty box)/50 and correctly applying variance rules, it's a standard S3 technique with clear setup. The 7 marks reflect multiple calculation steps rather than conceptual difficulty, making it slightly above average but routine for this module.
Spec5.04a Linear combinations: E(aX+bY), Var(aX+bY)

2 Boxes of matches contain 50 matches. Full boxes have mean mass 20.0 grams and standard deviation 0.4 grams. Empty boxes have mean mass 12.5 grams and standard deviation 0.2 grams. Stating any assumptions that you need to make, calculate the mean and standard deviation of the mass of a match. [7]

AnswerMarks Guidance
Assume \(F = E + M_1 + M_2 + \ldots + M_{50}\) where masses are independent and mass of empty box is independent of masses of matchesB1 For one relevant valid assumption
B1For another relevant valid assumption
\(20.0 = 12.5 + 50\mu\) giving mean mass of a match is 0.15 gramsM1 For attempting \(E(F)\) in terms of \(\mu\)
A1For correct value 0.15
\(0.4^2 = 0.2^2 + 50\sigma^2\)M1 For attempting \(\text{Var}(F)\) as a sum
A1For correct equation
Standard deviation is 0.049 gramsA1 7
Assume $F = E + M_1 + M_2 + \ldots + M_{50}$ where masses are independent and mass of empty box is independent of masses of matches | B1 | For one relevant valid assumption
| B1 | For another relevant valid assumption
$20.0 = 12.5 + 50\mu$ giving mean mass of a match is 0.15 grams | M1 | For attempting $E(F)$ in terms of $\mu$
| A1 | For correct value 0.15
$0.4^2 = 0.2^2 + 50\sigma^2$ | M1 | For attempting $\text{Var}(F)$ as a sum
| A1 | For correct equation
Standard deviation is 0.049 grams | A1 | 7 | For correct value 0.049
2 Boxes of matches contain 50 matches. Full boxes have mean mass 20.0 grams and standard deviation 0.4 grams. Empty boxes have mean mass 12.5 grams and standard deviation 0.2 grams. Stating any assumptions that you need to make, calculate the mean and standard deviation of the mass of a match. [7]

\hfill \mbox{\textit{OCR S3  Q2 [7]}}