OCR S3 2006 June — Question 3 7 marks

Exam BoardOCR
ModuleS3 (Statistics 3)
Year2006
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicT-tests (unknown variance)
TypePaired sample t-test
DifficultyStandard +0.3 This is a standard paired t-test application with all necessary statistics provided (sample means, variance estimate, sample size). Students must state the normality assumption, calculate the test statistic using the given values, and compare to critical values. It requires straightforward application of a learned procedure with no conceptual complications or novel problem-solving, making it slightly easier than average.
Spec5.05c Hypothesis test: normal distribution for population mean

3 Ten randomly chosen athletes were coached for a 200 m event. For each athlete, the times taken to run 200 m before and after coaching were measured. The sample mean times before and after coaching were 23.43 seconds and 22.84 seconds respectively. For each athlete the difference, \(d\) seconds, in the times before and after coaching was calculated and an unbiased estimate of the population variance of \(d\) was found to be 0.548 . Stating any required assumption, test at the \(5 \%\) significance level whether the population mean time for the 200 m run decreased after coaching.

Question 3:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Assume population of differences has a normal distribution or sample randomB1 Either assumption. AEF
\(H_0: \mu_B - \mu_A = 0\), \(H_1: \mu_B - \mu_A > 0\)B1
\(t = (23.43 - 22.84)/\sqrt{(0.548/10)}\)M1
\(= 2.520\) A1
\(CV = 1.833\)B1 Seen
\(2.52 >\) CV so reject \(H_0\)M1 Allow from CV \(2.262\) (2-tail)
\(1.812, 1.734\)
Accept that there is evidence that mean time has reducedA1\(\sqrt{}\) 7
# Question 3:

| Answer/Working | Marks | Guidance |
|---|---|---|
| Assume population of differences has a normal distribution or sample random | B1 | Either assumption. AEF |
| $H_0: \mu_B - \mu_A = 0$, $H_1: \mu_B - \mu_A > 0$ | B1 | |
| $t = (23.43 - 22.84)/\sqrt{(0.548/10)}$ | M1 | |
| $= 2.520$ | | A1 | |
| $CV = 1.833$ | B1 | Seen |
| $2.52 >$ CV so reject $H_0$ | M1 | Allow from CV $2.262$ (2-tail) |
| $1.812, 1.734$ | | |
| Accept that there is evidence that mean time has reduced | A1$\sqrt{}$ | **7** | ft wrong CV |

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3 Ten randomly chosen athletes were coached for a 200 m event. For each athlete, the times taken to run 200 m before and after coaching were measured. The sample mean times before and after coaching were 23.43 seconds and 22.84 seconds respectively. For each athlete the difference, $d$ seconds, in the times before and after coaching was calculated and an unbiased estimate of the population variance of $d$ was found to be 0.548 . Stating any required assumption, test at the $5 \%$ significance level whether the population mean time for the 200 m run decreased after coaching.

\hfill \mbox{\textit{OCR S3 2006 Q3 [7]}}