Easy -1.2 This is a straightforward application of the parallel lines property (same gradient) requiring only substitution into y = mx + c. It involves minimal steps: identify m = 5, substitute the point (2,13) to find c = 3, giving y = 5x + 3. This is easier than average as it's purely procedural with no problem-solving required.
3 Find the equation of the line which is parallel to \(y = 5 x - 4\) and which passes through the point (2,13). Give your answer in the form \(y = a x + b\).
or M1 for \(y - b = 5(x-a)\) with wrong \(a\), \(b\) or for \(y - 13 =\) their \(5(x-2)\) oe
or M1 for \(y = 5x\ [+k]\) [\(k\) = letter or number other than \(-4\)] and M1 for \(13 =\) their \(m \times 2 + k\)
M1
M0 for first M if \(-1/5\) used as gradient even if 5 seen first; second M still available if earned
## Question 3:
| Answer/Working | Mark | Guidance |
|---|---|---|
| $y = 5x + 3$ | 3 | |
| **M2** for $y - 13 = 5(x-2)$ oe | M2 | or **M1** for $y - b = 5(x-a)$ with wrong $a$, $b$ or for $y - 13 =$ their $5(x-2)$ oe |
| or **M1** for $y = 5x\ [+k]$ [$k$ = letter or number other than $-4$] and **M1** for $13 =$ their $m \times 2 + k$ | M1 | **M0** for first M if $-1/5$ used as gradient even if 5 seen first; second M still available if earned |
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3 Find the equation of the line which is parallel to $y = 5 x - 4$ and which passes through the point (2,13). Give your answer in the form $y = a x + b$.
\hfill \mbox{\textit{OCR MEI C1 Q3 [3]}}