Easy -1.2 This is a straightforward application of the gradient formula or point-slope form requiring only one calculation step: using m = (k-(-5))/(5-1) = 3 to solve for k. It's simpler than average A-level questions as it involves basic algebraic manipulation with no problem-solving insight needed.
M1 for \(\frac{k-(-5)}{5-1} = 3\) or other correct use of gradient eg triangle with 4 across, 12 up
M1
or M1 for correct method for eqn of line and \(x=5\) subst in their eqn and evaluated to find \(k\); or M1 for both of \(y - k = 3(x-5)\) oe and \(y-(-5) = 3(x-1)\) oe
## Question 2:
| Answer/Working | Mark | Guidance |
|---|---|---|
| $y = 7$ or $(5, 7)$ | 2 | condone omission of brackets |
| **M1** for $\frac{k-(-5)}{5-1} = 3$ or other correct use of gradient eg triangle with 4 across, 12 up | M1 | or M1 for correct method for eqn of line and $x=5$ subst in their eqn and evaluated to find $k$; or M1 for both of $y - k = 3(x-5)$ oe and $y-(-5) = 3(x-1)$ oe |
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2 A line has gradient 3 and passes through the point $( 1 , - 5 )$. The point $( 5 , k )$ is on this line. Find the value of $k$.
\hfill \mbox{\textit{OCR MEI C1 Q2 [2]}}