Easy -1.8 This is a straightforward linear inequality requiring only basic algebraic manipulation: multiply through by 2, collect like terms, and divide by the coefficient. It's a routine C1 exercise with no conceptual challenges beyond elementary algebra, making it significantly easier than average A-level questions.
Condone \(=\) used for first two Ms; M0 for just \(5x-3 < 2(x+5)\)
\(3x < 13\)
M1
Or \(-13 < -3x\) or ft
\(x < \frac{13}{3}\) o.e.
M1
Or ft; isw further simplification of \(13/3\); M0 for just \(x < 4.3\)
## Question 8:
| Answer | Marks | Guidance |
|--------|-------|----------|
| $5x-3 < 2x+10$ | M1 | Condone $=$ used for first two Ms; M0 for just $5x-3 < 2(x+5)$ |
| $3x < 13$ | M1 | Or $-13 < -3x$ or ft |
| $x < \frac{13}{3}$ o.e. | M1 | Or ft; isw further simplification of $13/3$; M0 for just $x < 4.3$ |
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