OCR S2 Specimen — Question 3 6 marks

Exam BoardOCR
ModuleS2 (Statistics 2)
SessionSpecimen
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicApproximating Binomial to Normal Distribution
TypeSingle probability inequality
DifficultyModerate -0.3 This is a straightforward application of the normal approximation to the binomial distribution. Part (i) is trivial probability multiplication (1/36), and part (ii) requires standard technique: identify binomial parameters, check approximation validity, apply continuity correction, and use normal tables. The question is slightly easier than average because it's a direct textbook-style application with clear setup and no conceptual obstacles.
Spec2.03a Mutually exclusive and independent events2.04d Normal approximation to binomial5.04a Linear combinations: E(aX+bY), Var(aX+bY)

3 Sixty people each make two throws with a fair six-sided die.
  1. State the probability of one particular person obtaining two sixes.
  2. Using a suitable approximation, calculate the probability that at least four of the sixty obtain two sixes.

AnswerMarks Guidance
(i) \(\frac{1}{36}\)B1 For correct probability
(ii) Number obtaining two sixes ~ \(\text{B}(60, \frac{1}{36})\)M1 For stating or implying binomial distribution
Approximate distribution is \(\text{Po}(\frac{5}{3})\)A1 For the correct Poisson approximation
\(\text{P}(\geq 4) = 1 - e^{-1}\left\{1 + \frac{5}{3} + \frac{(5/3)^2}{2!} + \frac{(5/3)^3}{3!}\right\}\)M1 For calculation of correct terms
M1For correct use of Poisson formula
\(= 0.0883\)A1 For correct answer 0.088(3)
Total: 6 marks
(i) $\frac{1}{36}$ | B1 | For correct probability

(ii) Number obtaining two sixes ~ $\text{B}(60, \frac{1}{36})$ | M1 | For stating or implying binomial distribution

Approximate distribution is $\text{Po}(\frac{5}{3})$ | A1 | For the correct Poisson approximation

$\text{P}(\geq 4) = 1 - e^{-1}\left\{1 + \frac{5}{3} + \frac{(5/3)^2}{2!} + \frac{(5/3)^3}{3!}\right\}$ | M1 | For calculation of correct terms
| M1 | For correct use of Poisson formula
$= 0.0883$ | A1 | For correct answer 0.088(3)

**Total: 6 marks**

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3 Sixty people each make two throws with a fair six-sided die.\\
(i) State the probability of one particular person obtaining two sixes.\\
(ii) Using a suitable approximation, calculate the probability that at least four of the sixty obtain two sixes.

\hfill \mbox{\textit{OCR S2  Q3 [6]}}