CAIE P2 2020 November — Question 7 10 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2020
SessionNovember
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicParametric differentiation
TypeGradient condition leads to trig equation
DifficultyStandard +0.3 This is a standard parametric differentiation question requiring dy/dx = (dy/dt)/(dx/dt), followed by routine harmonic form conversion and solving. All techniques are textbook exercises with no novel insight required, making it slightly easier than average.
Spec1.03g Parametric equations: of curves and conversion to cartesian1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals1.07s Parametric and implicit differentiation

7 A curve is defined by the parametric equations $$x = 3 t - 2 \sin t , \quad y = 5 t + 4 \cos t$$ where \(0 \leqslant t \leqslant 2 \pi\). At each of the points \(P\) and \(Q\) on the curve, the gradient of the curve is \(\frac { 5 } { 2 }\).
  1. Show that the values of \(t\) at \(P\) and \(Q\) satisfy the equation \(10 \cos t - 8 \sin t = 5\).
  2. Express \(10 \cos t - 8 \sin t\) in the form \(R \cos ( t + \alpha )\), where \(R > 0\) and \(0 < \alpha < \frac { 1 } { 2 } \pi\). Give the exact value of \(R\) and the value of \(\alpha\) correct to 3 significant figures.
  3. Hence find the values of \(t\) at the points \(P\) and \(Q\).

Question 7(a):
AnswerMarks Guidance
AnswerMark Guidance
Obtain \(\frac{dx}{dt} = 3 - 2\cos t\) and \(\frac{dy}{dt} = 5 - 4\sin t\)B1
Equate expression for \(\frac{dy}{dx}\) to \(\frac{5}{2}\)M1
Obtain \(10\cos t - 8\sin t = 5\)A1 AG – sufficient working to be shown
Question 7(b):
AnswerMarks Guidance
AnswerMark Guidance
State \(R = \sqrt{164}\) or exact equivalentB1
Use appropriate trigonometry to find \(\alpha\)M1
Obtain \(0.675\) with no errors seenA1 AWRT
Question 7(c):
AnswerMarks Guidance
AnswerMark Guidance
Carry out correct method to find one value of \(t\)M1 Must be using the result from (b)
Obtain \(0.495\)A1 AWRT
Carry out correct method to find second value of \(t\)M1
Obtain \(4.44\)A1 AWRT
## Question 7(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| Obtain $\frac{dx}{dt} = 3 - 2\cos t$ and $\frac{dy}{dt} = 5 - 4\sin t$ | B1 | |
| Equate expression for $\frac{dy}{dx}$ to $\frac{5}{2}$ | M1 | |
| Obtain $10\cos t - 8\sin t = 5$ | A1 | AG – sufficient working to be shown |

## Question 7(b):

| Answer | Mark | Guidance |
|--------|------|----------|
| State $R = \sqrt{164}$ or exact equivalent | B1 | |
| Use appropriate trigonometry to find $\alpha$ | M1 | |
| Obtain $0.675$ with no errors seen | A1 | AWRT |

## Question 7(c):

| Answer | Mark | Guidance |
|--------|------|----------|
| Carry out correct method to find one value of $t$ | M1 | Must be using the result from (b) |
| Obtain $0.495$ | A1 | AWRT |
| Carry out correct method to find second value of $t$ | M1 | |
| Obtain $4.44$ | A1 | AWRT |
7 A curve is defined by the parametric equations

$$x = 3 t - 2 \sin t , \quad y = 5 t + 4 \cos t$$

where $0 \leqslant t \leqslant 2 \pi$. At each of the points $P$ and $Q$ on the curve, the gradient of the curve is $\frac { 5 } { 2 }$.
\begin{enumerate}[label=(\alph*)]
\item Show that the values of $t$ at $P$ and $Q$ satisfy the equation $10 \cos t - 8 \sin t = 5$.
\item Express $10 \cos t - 8 \sin t$ in the form $R \cos ( t + \alpha )$, where $R > 0$ and $0 < \alpha < \frac { 1 } { 2 } \pi$. Give the exact value of $R$ and the value of $\alpha$ correct to 3 significant figures.
\item Hence find the values of $t$ at the points $P$ and $Q$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2020 Q7 [10]}}