| Exam Board | OCR |
|---|---|
| Module | C1 (Core Mathematics 1) |
| Marks | 6 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Straight Lines & Coordinate Geometry |
| Type | Midpoint of line segment |
| Difficulty | Moderate -0.3 This question requires finding axis intercepts (routine substitution), calculating a midpoint (direct formula application), then finding a distance from origin (Pythagoras). While it involves multiple steps and simplifying to the form k√5, each individual step is standard C1 technique with no problem-solving insight required. Slightly easier than average due to straightforward procedure. |
| Spec | 1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.10f Distance between points: using position vectors |
\begin{enumerate}
\item The straight line $l$ has the equation $x - 2 y = 12$ and meets the coordinate axes at the points $A$ and $B$.
\end{enumerate}
Find the distance of the mid-point of $A B$ from the origin, giving your answer in the form $k \sqrt { 5 }$.\\
\hfill \mbox{\textit{OCR C1 Q3 [6]}}