OCR C1 — Question 8 9 marks

Exam BoardOCR
ModuleC1 (Core Mathematics 1)
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCircles
TypeDistance from centre to line
DifficultyStandard +0.3 This is a straightforward multi-part question requiring completing the square to find circle centre/radius (standard C1 technique), then finding the perpendicular distance from centre to line using basic coordinate geometry. All steps are routine textbook exercises with no novel problem-solving required, making it slightly easier than average.
Spec1.03a Straight lines: equation forms y=mx+c, ax+by+c=01.03d Circles: equation (x-a)^2+(y-b)^2=r^21.03e Complete the square: find centre and radius of circle

8.
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The diagram shows the circle with equation \(x ^ { 2 } + y ^ { 2 } - 2 x - 18 y + 73 = 0\) and the straight line with equation \(y = 2 x - 3\).
  1. Find the coordinates of the centre and the radius of the circle.
  2. Find the coordinates of the point on the line which is closest to the circle.

AnswerMarks Guidance
(i) \((x-1)^2 + (y-9)^2 = 9\)M1 A2
Centre \((1,9)\), radius \(= 3\)
(ii) Gradient of line \(= 2\)M1
Perpendicular gradient \(= -\frac{1}{2}\)M1
Equation of line through centre of circle, perpendicular to straight line: \(y - 9 = -\frac{1}{2}(x-1)\)M1
\(y = \frac{19}{2} - \frac{1}{2}x\)A1
Closest point where lines intersect: \(2x - 3 = \frac{19}{2} - \frac{1}{2}x\)M1
\(x = 5\)A1
\(\therefore (5,7)\)A1 (9)
**(i)** $(x-1)^2 + (y-9)^2 = 9$ | M1 A2 | 
Centre $(1,9)$, radius $= 3$ | |

**(ii)** Gradient of line $= 2$ | M1 |
Perpendicular gradient $= -\frac{1}{2}$ | M1 |
Equation of line through centre of circle, perpendicular to straight line: $y - 9 = -\frac{1}{2}(x-1)$ | M1 |
$y = \frac{19}{2} - \frac{1}{2}x$ | A1 |
Closest point where lines intersect: $2x - 3 = \frac{19}{2} - \frac{1}{2}x$ | M1 |
$x = 5$ | A1 |
$\therefore (5,7)$ | A1 | **(9)**

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8.

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\includegraphics[max width=\textwidth, alt={}]{4fa65854-801c-4a93-866e-796c000a649f-2_675_689_251_495}
\end{center}

The diagram shows the circle with equation $x ^ { 2 } + y ^ { 2 } - 2 x - 18 y + 73 = 0$ and the straight line with equation $y = 2 x - 3$.\\
(i) Find the coordinates of the centre and the radius of the circle.\\
(ii) Find the coordinates of the point on the line which is closest to the circle.\\

\hfill \mbox{\textit{OCR C1  Q8 [9]}}