OCR MEI C1 2009 January — Question 4 3 marks

Exam BoardOCR MEI
ModuleC1 (Core Mathematics 1)
Year2009
SessionJanuary
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicFactor & Remainder Theorem
TypeSingle unknown constant
DifficultyModerate -0.8 This is a straightforward application of the factor theorem requiring only substitution of x=2 into f(x)=0 and solving a simple linear equation for a. It's a single-step problem with minimal algebraic manipulation, making it easier than average but not trivial since it requires understanding the factor theorem concept.
Spec1.02j Manipulate polynomials: expanding, factorising, division, factor theorem

4 You are given that \(\mathrm { f } ( x ) = x ^ { 4 } + a x - 6\) and that \(x - 2\) is a factor of \(\mathrm { f } ( x )\).
Find the value of \(a\).

4 You are given that $\mathrm { f } ( x ) = x ^ { 4 } + a x - 6$ and that $x - 2$ is a factor of $\mathrm { f } ( x )$.\\
Find the value of $a$.

\hfill \mbox{\textit{OCR MEI C1 2009 Q4 [3]}}