CAIE P2 2023 June — Question 6 10 marks

Exam BoardCAIE
ModuleP2 (Pure Mathematics 2)
Year2023
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAddition & Double Angle Formulae
TypeProve identity then find exact value and solve/integrate
DifficultyStandard +0.3 This is a structured multi-part question testing standard addition formulae and product-to-sum identities. Part (a) requires applying compound angle formulae systematically but follows a predictable path. Parts (b) and (c) are direct applications of the proven identity with straightforward substitutions and routine integration. While it requires multiple techniques, each step is standard bookwork with no novel insight needed, making it slightly easier than average.
Spec1.05g Exact trigonometric values: for standard angles1.05l Double angle formulae: and compound angle formulae1.08c Integrate e^(kx), 1/x, sin(kx), cos(kx)

6
  1. Show that \(4 \sin \left( \theta + \frac { 1 } { 3 } \pi \right) \cos \left( \theta - \frac { 1 } { 3 } \pi \right) \equiv \sqrt { 3 } + 2 \sin 2 \theta\).
  2. Find the exact value of \(4 \sin \frac { 17 } { 24 } \pi \cos \frac { 1 } { 24 } \pi\).
  3. Find the exact value of \(\int _ { 0 } ^ { \frac { 1 } { 8 } \pi } 4 \sin \left( 2 x + \frac { 1 } { 3 } \pi \right) \cos \left( 2 x - \frac { 1 } { 3 } \pi \right) \mathrm { d } x\).

Question 6(a):
AnswerMarks Guidance
AnswerMarks Guidance
Obtain at least either \((\frac{1}{2}\sin\theta + \frac{1}{2}\sqrt{3}\cos\theta)\) or \((\frac{1}{2}\cos\theta + \frac{1}{2}\sqrt{3}\sin\theta)\)B1 Allow if implied by decimal values
Expand and simplify with correct use of \(\sin^2\theta + \cos^2\theta = 1\)M1
Use \(\sin\theta\cos\theta = \frac{1}{2}\sin 2\theta\)M1
Confirm given result \(\sqrt{3} + 2\sin 2\theta\)A1 AG necessary detail required
Question 6(b):
AnswerMarks Guidance
AnswerMarks Guidance
Identify value of \(\theta\) is \(\frac{3}{8}\pi\)*B1 OE
Obtain \(\sqrt{3} + 2\sin\frac{3}{4}\pi\) and conclude \(\sqrt{3} + \sqrt{2}\)DB1 Or exact equivalent
Question 6(c):
AnswerMarks Guidance
AnswerMarks Guidance
Identify integrand as \(\sqrt{3} + 2\sin 4x\)B1
Integrate to obtain form \(k_1 x + k_2\cos 4x\)M1 Where \(k_1 k_2 \neq 0\)
Obtain correct \(\sqrt{3}\,x - \frac{1}{2}\cos 4x\)A1
Obtain \(\frac{1}{8}\pi\sqrt{3} + \frac{1}{2}\)A1 Or exact equivalent
## Question 6(a):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Obtain at least either $(\frac{1}{2}\sin\theta + \frac{1}{2}\sqrt{3}\cos\theta)$ or $(\frac{1}{2}\cos\theta + \frac{1}{2}\sqrt{3}\sin\theta)$ | B1 | Allow if implied by decimal values |
| Expand and simplify with correct use of $\sin^2\theta + \cos^2\theta = 1$ | M1 | |
| Use $\sin\theta\cos\theta = \frac{1}{2}\sin 2\theta$ | M1 | |
| Confirm given result $\sqrt{3} + 2\sin 2\theta$ | A1 | AG necessary detail required |

## Question 6(b):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Identify value of $\theta$ is $\frac{3}{8}\pi$ | *B1 | OE |
| Obtain $\sqrt{3} + 2\sin\frac{3}{4}\pi$ and conclude $\sqrt{3} + \sqrt{2}$ | DB1 | Or exact equivalent |

## Question 6(c):

| Answer | Marks | Guidance |
|--------|-------|----------|
| Identify integrand as $\sqrt{3} + 2\sin 4x$ | B1 | |
| Integrate to obtain form $k_1 x + k_2\cos 4x$ | M1 | Where $k_1 k_2 \neq 0$ |
| Obtain correct $\sqrt{3}\,x - \frac{1}{2}\cos 4x$ | A1 | |
| Obtain $\frac{1}{8}\pi\sqrt{3} + \frac{1}{2}$ | A1 | Or exact equivalent |

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6
\begin{enumerate}[label=(\alph*)]
\item Show that $4 \sin \left( \theta + \frac { 1 } { 3 } \pi \right) \cos \left( \theta - \frac { 1 } { 3 } \pi \right) \equiv \sqrt { 3 } + 2 \sin 2 \theta$.
\item Find the exact value of $4 \sin \frac { 17 } { 24 } \pi \cos \frac { 1 } { 24 } \pi$.
\item Find the exact value of $\int _ { 0 } ^ { \frac { 1 } { 8 } \pi } 4 \sin \left( 2 x + \frac { 1 } { 3 } \pi \right) \cos \left( 2 x - \frac { 1 } { 3 } \pi \right) \mathrm { d } x$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P2 2023 Q6 [10]}}