| Exam Board | OCR MEI |
|---|---|
| Module | S1 (Statistics 1) |
| Marks | 18 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Data representation |
| Type | Outliers from cumulative frequency diagram |
| Difficulty | Moderate -0.3 This is a multi-part question covering standard cumulative frequency diagram reading (median, quartiles, percentiles) and basic binomial probability calculations. While it has many parts (6 sub-questions), each individual component is routine: reading values from a graph, applying the 1.5×IQR outlier rule, and straightforward binomial probability computations. The question requires no novel insight or complex problem-solving, just systematic application of well-practiced techniques. It's slightly easier than average due to its procedural nature, though the multiple parts and marks elevate it slightly from being significantly below average. |
| Spec | 2.02f Measures of average and spread2.02h Recognize outliers2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities |
| Answer | Marks |
|---|---|
| Median = 3370 | B1 |
| \(Q_1\) = 3050 | B1 |
| \(Q_3\) = 3700 | B1 |
| Inter-quartile range = 3700 – 3050 = 650 | B1 |
| Answer | Marks |
|---|---|
| Lower limit 3050 – 1.5 × 650 = 2075 | B1 |
| Upper limit 3700 + 1.5 × 650 = 4675 | B1 |
| Approx 40 babies below 2075 and 5 above 4675 | M1 |
| so total 45 | A1 |
| Answer | Marks |
|---|---|
| Decision based on convincing argument: eg 'no, because there is nothing to suggest that they are not genuine data items and these data may influence health care provision' | E2 |
| Answer | Marks |
|---|---|
| All babies below 2600 grams in weight | B2 CAO |
| Answer | Marks |
|---|---|
| \(X \sim B(17, 0.12)\) | M1 |
| \(P(X = 2) = \binom{17}{2} \times 0.12^2 \times 0.88^{15}\) | M1 |
| \(P(X = 2) = 0.2878\) | A1 CAO |
| \(P(X > 2) = 1 – [P(X=0) + P(X=1) + P(X=2)]\) | M1 |
| \(P(X=1) = \binom{17}{1} \times 0.12 \times 0.88^{16}\) | M1 |
| \(P(X > 2) = 1 – (0.2878 + 0.2638 + 0.1138) = 0.335\) | A1 CAO |
| Answer | Marks |
|---|---|
| Expected number of occasions is 33.5 | B1 FT |
# Question 1
## (i)
Median = 3370 | B1
$Q_1$ = 3050 | B1
$Q_3$ = 3700 | B1
Inter-quartile range = 3700 – 3050 = 650 | B1
## (ii)
Lower limit 3050 – 1.5 × 650 = 2075 | B1
Upper limit 3700 + 1.5 × 650 = 4675 | B1
Approx 40 babies below 2075 and 5 above 4675 | M1
so total 45 | A1
## (iii)
Decision based on convincing argument: eg 'no, because there is nothing to suggest that they are not genuine data items and these data may influence health care provision' | E2
## (iv)
All babies below 2600 grams in weight | B2 CAO
## (v)
$X \sim B(17, 0.12)$ | M1
$P(X = 2) = \binom{17}{2} \times 0.12^2 \times 0.88^{15}$ | M1
$P(X = 2) = 0.2878$ | A1 CAO
$P(X > 2) = 1 – [P(X=0) + P(X=1) + P(X=2)]$ | M1
$P(X=1) = \binom{17}{1} \times 0.12 \times 0.88^{16}$ | M1
$P(X > 2) = 1 – (0.2878 + 0.2638 + 0.1138) = 0.335$ | A1 CAO
## (vi)
Expected number of occasions is 33.5 | B1 FT
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**TOTAL: 18 marks**1 The birth weights in grams of a random sample of 1000 babies are displayed in the cumulative frequency diagram below.\\
\includegraphics[max width=\textwidth, alt={}, center]{088972e9-bfcd-429c-9145-af274a4c0a58-1_1268_1548_472_335}
\begin{enumerate}[label=(\roman*)]
\item Use the diagram to estimate the median and interquartile range of the data.
\item Use your answers to part (i) to estimate the number of outliers in the sample.
\item Should these outliers be excluded from any further analysis? Briefly explain your answer.
\item Any baby whose weight is below the 10th percentile is selected for careful monitoring. Use the diagram to determine the range of weights of the babies who are selected.\\
$12 \%$ of new-born babies require some form of special care. A maternity unit has 17 new-born babies. You may assume that these 17 babies form an independent random sample.
\item Find the probability that\\
(A) exactly 2 of these 17 babies require special care,\\
(B) more than 2 of the 17 babies require special care.
\item On 100 independent occasions the unit has 17 babies. Find the expected number of occasions on which there would be more than 2 babies who require special care.
\end{enumerate}
\hfill \mbox{\textit{OCR MEI S1 Q1 [18]}}