OCR FP3 2007 June — Question 3 6 marks

Exam BoardOCR
ModuleFP3 (Further Pure Mathematics 3)
Year2007
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicSecond order differential equations
TypeStandard non-homogeneous with exponential RHS
DifficultyStandard +0.8 This is a standard second-order linear differential equation with constant coefficients and exponential RHS from Further Maths FP3. While the method is routine (find complementary function via auxiliary equation, then particular integral), it requires multiple techniques and careful algebra. The exponential RHS (e^{3x}) doesn't match either root of the auxiliary equation (2 and 4), making it straightforward but still requiring competent execution across several steps—moderately above average difficulty.
Spec4.10d Second order homogeneous: auxiliary equation method4.10e Second order non-homogeneous: complementary + particular integral

3 Find the general solution of the differential equation $$\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } } - 6 \frac { \mathrm {~d} y } { \mathrm {~d} x } + 8 y = \mathrm { e } ^ { 3 x } .$$

AnswerMarks Guidance
Aux. equation \(m^2 - 6m + 8 = (0)\)M1 For auxiliary equation seen
\(m = 2, 4\)A1 For correct roots
CF \(y = Ae^{2x} + Be^{4x}\)A1√ For correct CF, f.t. from their \(m\)
PI \((y =) Ce^{3x}\)M1 For stating and substituting PI of correct form
\(9C - 18C + 8C = 1 \Rightarrow C = -1\)A1 For correct value of \(C\)
GS \(y = Ae^{2x} + Be^{4x} - e^{3x}\)B1√ 6 For GS, f.t. from their CF + PI with 2 arbitrary constants in CF and none in PI
**Aux. equation** $m^2 - 6m + 8 = (0)$ | M1 | For auxiliary equation seen

$m = 2, 4$ | A1 | For correct roots

**CF** $y = Ae^{2x} + Be^{4x}$ | A1√ | For correct CF, f.t. from their $m$

**PI** $(y =) Ce^{3x}$ | M1 | For stating and substituting PI of correct form

$9C - 18C + 8C = 1 \Rightarrow C = -1$ | A1 | For correct value of $C$

**GS** $y = Ae^{2x} + Be^{4x} - e^{3x}$ | B1√ 6 | For GS, f.t. from their CF + PI with 2 arbitrary constants in CF and none in PI
3 Find the general solution of the differential equation

$$\frac { \mathrm { d } ^ { 2 } y } { \mathrm {~d} x ^ { 2 } } - 6 \frac { \mathrm {~d} y } { \mathrm {~d} x } + 8 y = \mathrm { e } ^ { 3 x } .$$

\hfill \mbox{\textit{OCR FP3 2007 Q3 [6]}}