| Exam Board | OCR |
|---|---|
| Module | FP3 (Further Pure Mathematics 3) |
| Year | 2007 |
| Session | January |
| Marks | 13 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Vectors: Lines & Planes |
| Type | Line intersection with plane |
| Difficulty | Standard +0.3 This is a standard Further Maths vectors question involving routine techniques: writing a line equation, finding intersection with a plane (given the answer to verify), calculating ratios, and position vectors along a line. All parts are straightforward applications of vector methods with no novel problem-solving required, making it slightly easier than average even for FM. |
| Spec | 1.10a Vectors in 2D: i,j notation and column vectors1.10b Vectors in 3D: i,j,k notation4.04a Line equations: 2D and 3D, cartesian and vector forms4.04b Plane equations: cartesian and vector forms4.04f Line-plane intersection: find point |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| EITHER: AG is \(\mathbf{r}=[6,4,8]+tk[1,0,1]\) or \([3,4,5]+tk[1,0,1]\) | B1 | For a correct equation |
| Normal to \(BCD\) is \(\mathbf{n}=k[1,1,-3]\) | M1, A1 | For finding vector product of any two of \(\pm[1,-4,-1]\), \(\pm[2,1,1]\), \(\pm[1,5,2]\); for correct n |
| Equation of \(BCD\) is \(\mathbf{r}.[1,1,-3]=-6\) | A1 | For correct equation (or in cartesian form) |
| Intersect at \((6+t)+4+(-3)(8+t)=-6\) | M1 | For substituting point on \(AG\) into plane |
| \(t=-4\ (t=-1\) using \([3,4,5])\Rightarrow\mathbf{OM}=[2,4,4]\) | A1 | For correct position vector of \(M\) AG |
| OR: \(\mathbf{r}=\mathbf{u}+\lambda\mathbf{v}+\mu\mathbf{w}\) approach | B1 | For a correct equation |
| \(\mathbf{u}=[2,1,3]\) or \([1,5,4]\) or \([3,6,5]\); v,w two of \([1,-4,-1],[1,5,2],[2,1,1]\) | M1, A1 | For a correct parametric equation of \(BCD\) |
| Forming 3 equations in \(t,\lambda,\mu\) | M1 | For forming 3 equations in \(t,\lambda,\mu\) from line and plane, and attempting to solve them |
| \(t=-4\) or \(\lambda=-\frac{1}{3}\), \(\mu=\frac{1}{3}\) | A1 | For correct value of \(t\) or \(\lambda\), \(\mu\) |
| \(\Rightarrow\mathbf{OM}=[2,4,4]\) | A1 6 | For correct position vector of \(M\) AG |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(A,G,M\) have \(t=0,-3,-4\) OR \(AG=3\sqrt{2}\), \(AM=4\sqrt{2}\) OR \(\mathbf{AG}=[-3,0,-3]\), \(\mathbf{AM}=[-4,0,-4]\) \(\Rightarrow AG:AM=3:4\) | B1 1 | For correct ratio AEF |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| \(\mathbf{OP}=\mathbf{OC}+\frac{4}{3}\mathbf{CG}\) | M1 | For using given ratio to find position vector of \(P\) |
| \(=\left[\frac{11}{3},\frac{11}{3},\frac{16}{3}\right]\) | A1 2 | For correct vector |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Mark | Guidance |
| EITHER: Normal to \(ABD\) is \(\mathbf{n}=k[19,3,-17]\) | M1, A1 | For finding vector product of any two of \(\pm[4,3,5]\), \(\pm[1,5,2]\), \(\pm[3,-2,3]\); for correct n |
| Equation of \(ABD\) is \(\mathbf{r}.[19,3,-17]=-10\) | M1 | For finding equation (or in cartesian form) |
| \(19\cdot\frac{11}{3}+3\cdot\frac{11}{3}-17\cdot\frac{16}{3}=-10\) | A1 | For verifying that \(P\) satisfies equation |
| OR: Equation of \(ABD\) is \(\mathbf{r}=[6,4,8]+\lambda[4,3,5]+\mu[1,5,2]\) (etc.) | M1 | For finding equation in parametric form |
| \(\left[\frac{11}{3},\frac{11}{3},\frac{16}{3}\right]=[6,4,8]+\lambda[4,3,5]+\mu[1,5,2]\) | M1 | For substituting \(P\) and solving 2 equations for \(\lambda\), \(\mu\) |
| \(\lambda=-\frac{2}{3}\), \(\mu=\frac{1}{3}\) | A1 | For correct \(\lambda\), \(\mu\) |
| Verifying 3rd equation is satisfied | A1 | |
| OR: \(\mathbf{AP}=\left[-\frac{7}{3},-\frac{1}{3},-\frac{8}{3}\right]\) | M1 | For finding 3 relevant vectors in plane \(ABDP\) |
| \(\mathbf{AB}=[-4,-3,-5]\), \(\mathbf{AD}=[-3,2,-3]\) | A1 | For correct AP or BP or DP |
| \(\Rightarrow\mathbf{AB}+\mathbf{AD}=[-7,-1,-8]\) | M1 | For finding AB, AD or BA, BD or DB, DA |
| \(\Rightarrow\mathbf{AP}=\frac{1}{3}(\mathbf{AB}+\mathbf{AD})\) | A1 4 | For verifying linear relationship |
## Question 7:
### Part (i)
| Answer/Working | Mark | Guidance |
|---|---|---|
| EITHER: AG is $\mathbf{r}=[6,4,8]+tk[1,0,1]$ or $[3,4,5]+tk[1,0,1]$ | B1 | For a correct equation |
| Normal to $BCD$ is $\mathbf{n}=k[1,1,-3]$ | M1, A1 | For finding vector product of any two of $\pm[1,-4,-1]$, $\pm[2,1,1]$, $\pm[1,5,2]$; for correct **n** |
| Equation of $BCD$ is $\mathbf{r}.[1,1,-3]=-6$ | A1 | For correct equation (or in cartesian form) |
| Intersect at $(6+t)+4+(-3)(8+t)=-6$ | M1 | For substituting point on $AG$ into plane |
| $t=-4\ (t=-1$ using $[3,4,5])\Rightarrow\mathbf{OM}=[2,4,4]$ | A1 | For correct position vector of $M$ AG |
| OR: $\mathbf{r}=\mathbf{u}+\lambda\mathbf{v}+\mu\mathbf{w}$ approach | B1 | For a correct equation |
| $\mathbf{u}=[2,1,3]$ or $[1,5,4]$ or $[3,6,5]$; **v**,**w** two of $[1,-4,-1],[1,5,2],[2,1,1]$ | M1, A1 | For a correct parametric equation of $BCD$ |
| Forming 3 equations in $t,\lambda,\mu$ | M1 | For forming 3 equations in $t,\lambda,\mu$ from line and plane, and attempting to solve them |
| $t=-4$ or $\lambda=-\frac{1}{3}$, $\mu=\frac{1}{3}$ | A1 | For correct value of $t$ or $\lambda$, $\mu$ |
| $\Rightarrow\mathbf{OM}=[2,4,4]$ | A1 **6** | For correct position vector of $M$ AG |
### Part (ii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $A,G,M$ have $t=0,-3,-4$ OR $AG=3\sqrt{2}$, $AM=4\sqrt{2}$ OR $\mathbf{AG}=[-3,0,-3]$, $\mathbf{AM}=[-4,0,-4]$ $\Rightarrow AG:AM=3:4$ | B1 **1** | For correct ratio AEF |
### Part (iii)
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\mathbf{OP}=\mathbf{OC}+\frac{4}{3}\mathbf{CG}$ | M1 | For using given ratio to find position vector of $P$ |
| $=\left[\frac{11}{3},\frac{11}{3},\frac{16}{3}\right]$ | A1 **2** | For correct vector |
### Part (iv)
| Answer/Working | Mark | Guidance |
|---|---|---|
| EITHER: Normal to $ABD$ is $\mathbf{n}=k[19,3,-17]$ | M1, A1 | For finding vector product of any two of $\pm[4,3,5]$, $\pm[1,5,2]$, $\pm[3,-2,3]$; for correct **n** |
| Equation of $ABD$ is $\mathbf{r}.[19,3,-17]=-10$ | M1 | For finding equation (or in cartesian form) |
| $19\cdot\frac{11}{3}+3\cdot\frac{11}{3}-17\cdot\frac{16}{3}=-10$ | A1 | For verifying that $P$ satisfies equation |
| OR: Equation of $ABD$ is $\mathbf{r}=[6,4,8]+\lambda[4,3,5]+\mu[1,5,2]$ (etc.) | M1 | For finding equation in parametric form |
| $\left[\frac{11}{3},\frac{11}{3},\frac{16}{3}\right]=[6,4,8]+\lambda[4,3,5]+\mu[1,5,2]$ | M1 | For substituting $P$ and solving 2 equations for $\lambda$, $\mu$ |
| $\lambda=-\frac{2}{3}$, $\mu=\frac{1}{3}$ | A1 | For correct $\lambda$, $\mu$ |
| Verifying 3rd equation is satisfied | A1 | |
| OR: $\mathbf{AP}=\left[-\frac{7}{3},-\frac{1}{3},-\frac{8}{3}\right]$ | M1 | For finding 3 relevant vectors in plane $ABDP$ |
| $\mathbf{AB}=[-4,-3,-5]$, $\mathbf{AD}=[-3,2,-3]$ | A1 | For correct **AP** or **BP** or **DP** |
| $\Rightarrow\mathbf{AB}+\mathbf{AD}=[-7,-1,-8]$ | M1 | For finding **AB**, **AD** or **BA**, **BD** or **DB**, **DA** |
| $\Rightarrow\mathbf{AP}=\frac{1}{3}(\mathbf{AB}+\mathbf{AD})$ | A1 **4** | For verifying linear relationship |
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7 The position vectors of the points $A , B , C , D , G$ are given by
$$\mathbf { a } = 6 \mathbf { i } + 4 \mathbf { j } + 8 \mathbf { k } , \quad \mathbf { b } = 2 \mathbf { i } + \mathbf { j } + 3 \mathbf { k } , \quad \mathbf { c } = \mathbf { i } + 5 \mathbf { j } + 4 \mathbf { k } , \quad \mathbf { d } = 3 \mathbf { i } + 6 \mathbf { j } + 5 \mathbf { k } , \quad \mathbf { g } = 3 \mathbf { i } + 4 \mathbf { j } + 5 \mathbf { k }$$
respectively.\\
(i) The line through $A$ and $G$ meets the plane $B C D$ at $M$. Write down the vector equation of the line through $A$ and $G$ and hence show that the position vector of $M$ is $2 \mathbf { i } + 4 \mathbf { j } + 4 \mathbf { k }$.\\
(ii) Find the value of the ratio $A G : A M$.\\
(iii) Find the position vector of the point $P$ on the line through $C$ and $G$, such that $\overrightarrow { C P } = \frac { 4 } { 3 } \overrightarrow { C G }$.\\
(iv) Verify that $P$ lies in the plane $A B D$.
\hfill \mbox{\textit{OCR FP3 2007 Q7 [13]}}