OCR MEI FP2 2008 June — Question 5 18 marks

Exam BoardOCR MEI
ModuleFP2 (Further Pure Mathematics 2)
Year2008
SessionJune
Marks18
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConic sections
TypeConic translation and transformation
DifficultyChallenging +1.2 This is a substantial Further Maths question requiring multiple techniques (parametric differentiation, trigonometric identities, algebraic manipulation) across six parts, but each individual step follows standard FP2 methods. The algebraic manipulation in part (iv) and the geometric interpretation require careful work but no novel insights, placing it moderately above average difficulty for A-level.
Spec1.02n Sketch curves: simple equations including polynomials1.02w Graph transformations: simple transformations of f(x)1.03g Parametric equations: of curves and conversion to cartesian

5 A curve has parametric equations \(x = \lambda \cos \theta - \frac { 1 } { \lambda } \sin \theta , y = \cos \theta + \sin \theta\), where \(\lambda\) is a positive constant.
  1. Use your calculator to obtain a sketch of the curve in each of the cases $$\lambda = 0.5 , \quad \lambda = 3 \quad \text { and } \quad \lambda = 5 .$$
  2. Given that the curve is a conic, name the type of conic.
  3. Show that \(y\) has a maximum value of \(\sqrt { 2 }\) when \(\theta = \frac { 1 } { 4 } \pi\).
  4. Show that \(x ^ { 2 } + y ^ { 2 } = \left( 1 + \lambda ^ { 2 } \right) + \left( \frac { 1 } { \lambda ^ { 2 } } - \lambda ^ { 2 } \right) \sin ^ { 2 } \theta\), and deduce that the distance from the origin of any point on the curve is between \(\sqrt { 1 + \frac { 1 } { \lambda ^ { 2 } } }\) and \(\sqrt { 1 + \lambda ^ { 2 } }\).
  5. For the case \(\lambda = 1\), show that the curve is a circle, and find its radius.
  6. For the case \(\lambda = 2\), draw a sketch of the curve, and label the points \(\mathrm { A } , \mathrm { B } , \mathrm { C } , \mathrm { D } , \mathrm { E } , \mathrm { F } , \mathrm { G } , \mathrm { H }\) on the curve corresponding to \(\theta = 0 , \frac { 1 } { 4 } \pi , \frac { 1 } { 2 } \pi , \frac { 3 } { 4 } \pi , \pi , \frac { 5 } { 4 } \pi , \frac { 3 } { 2 } \pi , \frac { 7 } { 4 } \pi\) respectively. You should make clear what is special about each of these points.

5 A curve has parametric equations $x = \lambda \cos \theta - \frac { 1 } { \lambda } \sin \theta , y = \cos \theta + \sin \theta$, where $\lambda$ is a positive constant.\\
(i) Use your calculator to obtain a sketch of the curve in each of the cases

$$\lambda = 0.5 , \quad \lambda = 3 \quad \text { and } \quad \lambda = 5 .$$

(ii) Given that the curve is a conic, name the type of conic.\\
(iii) Show that $y$ has a maximum value of $\sqrt { 2 }$ when $\theta = \frac { 1 } { 4 } \pi$.\\
(iv) Show that $x ^ { 2 } + y ^ { 2 } = \left( 1 + \lambda ^ { 2 } \right) + \left( \frac { 1 } { \lambda ^ { 2 } } - \lambda ^ { 2 } \right) \sin ^ { 2 } \theta$, and deduce that the distance from the origin of any point on the curve is between $\sqrt { 1 + \frac { 1 } { \lambda ^ { 2 } } }$ and $\sqrt { 1 + \lambda ^ { 2 } }$.\\
(v) For the case $\lambda = 1$, show that the curve is a circle, and find its radius.\\
(vi) For the case $\lambda = 2$, draw a sketch of the curve, and label the points $\mathrm { A } , \mathrm { B } , \mathrm { C } , \mathrm { D } , \mathrm { E } , \mathrm { F } , \mathrm { G } , \mathrm { H }$ on the curve corresponding to $\theta = 0 , \frac { 1 } { 4 } \pi , \frac { 1 } { 2 } \pi , \frac { 3 } { 4 } \pi , \pi , \frac { 5 } { 4 } \pi , \frac { 3 } { 2 } \pi , \frac { 7 } { 4 } \pi$ respectively. You should make clear what is special about each of these points.

\hfill \mbox{\textit{OCR MEI FP2 2008 Q5 [18]}}