Moderate -0.3 This is a straightforward parametric differentiation question requiring students to find dy/dx using the chain rule (dy/dt รท dx/dt), evaluate at t=0 to find the gradient, find the point coordinates, then write the tangent equation. It's slightly easier than average because it involves standard exponential differentiation with no algebraic complications, though it does require multiple routine steps.
3 A curve has parametric equations
$$x = \mathrm { e } ^ { t } - 2 \mathrm { e } ^ { - t } , \quad y = 3 \mathrm { e } ^ { 2 t } + 1$$
Find the equation of the tangent to the curve at the point for which \(t = 0\).
3 A curve has parametric equations
$$x = \mathrm { e } ^ { t } - 2 \mathrm { e } ^ { - t } , \quad y = 3 \mathrm { e } ^ { 2 t } + 1$$
Find the equation of the tangent to the curve at the point for which $t = 0$.\\
\hfill \mbox{\textit{CAIE P2 2020 Q3 [5]}}