Edexcel M1 2018 Specimen — Question 2 6 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2018
SessionSpecimen
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeDirect collision, find impulse magnitude
DifficultyModerate -0.3 This is a straightforward M1 momentum conservation problem requiring application of standard formulas. Part (a) uses conservation of momentum with clearly defined before/after velocities to find k (a simple algebraic equation). Part (b) applies the impulse-momentum theorem directly. While it requires careful sign handling and algebraic manipulation, it involves no novel insight—just methodical application of core mechanics principles that are extensively practiced in M1.
Spec6.03b Conservation of momentum: 1D two particles6.03f Impulse-momentum: relation

2. Two particles \(P\) and \(Q\) are moving in opposite directions along the same horizontal straight line. Particle \(P\) has mass \(m\) and particle \(Q\) has mass \(k m\). The particles collide directly. Immediately before the collision, the speed of \(P\) is \(u\) and the speed of \(Q\) is \(2 u\). As a result of the collision, the direction of motion of each particle is reversed and the speed of each particle is halved.
  1. Find the value of \(k\).
  2. Find, in terms of \(m\) and \(u\) only, the magnitude of the impulse exerted on \(Q\) by \(P\) in the collision.

Question 2:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(mu - 2kmu = -\frac{1}{2}mu + kmu\) or \(m\left(\frac{1}{2}u + u\right) = -km(-u - 2u)\)M1 Use of CLM or equal and opposite impulses. Need all 4 terms dimensionally correct. Masses and speeds must be paired correctly. Condone sign errors. Condone factor of \(g\) throughout.
Unsimplified equation with at most one errorA1
Correct unsimplified equationA1
\(k = \frac{1}{2}\)A1 From correct working only
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
For \(P\): \(I = \pm m(\frac{1}{2}u \pm -u)\); For \(Q\): \(I = \pm km(u \pm -2u)\)M1 Impulse on \(P\) or impulse on \(Q\). Mass must be used with correct speeds. e.g. \(km \times \frac{1}{2}u\) is M0. If working on \(Q\), allow equation using their \(k\). Terms must be dimensionally correct. Use of \(g\) is M0.
\(\frac{3mu}{2}\)A1 Only. From correct working only.
## Question 2:

### Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $mu - 2kmu = -\frac{1}{2}mu + kmu$ or $m\left(\frac{1}{2}u + u\right) = -km(-u - 2u)$ | M1 | Use of CLM or equal and opposite impulses. Need all 4 terms dimensionally correct. Masses and speeds must be paired correctly. Condone sign errors. Condone factor of $g$ throughout. |
| Unsimplified equation with at most one error | A1 | |
| Correct unsimplified equation | A1 | |
| $k = \frac{1}{2}$ | A1 | From correct working only |

### Part (b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| For $P$: $I = \pm m(\frac{1}{2}u \pm -u)$; For $Q$: $I = \pm km(u \pm -2u)$ | M1 | Impulse on $P$ or impulse on $Q$. Mass must be used with correct speeds. e.g. $km \times \frac{1}{2}u$ is M0. If working on $Q$, allow equation using their $k$. Terms must be dimensionally correct. Use of $g$ is M0. |
| $\frac{3mu}{2}$ | A1 | Only. From correct working only. |

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2. Two particles $P$ and $Q$ are moving in opposite directions along the same horizontal straight line. Particle $P$ has mass $m$ and particle $Q$ has mass $k m$. The particles collide directly. Immediately before the collision, the speed of $P$ is $u$ and the speed of $Q$ is $2 u$. As a result of the collision, the direction of motion of each particle is reversed and the speed of each particle is halved.
\begin{enumerate}[label=(\alph*)]
\item Find the value of $k$.
\item Find, in terms of $m$ and $u$ only, the magnitude of the impulse exerted on $Q$ by $P$ in the collision.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2018 Q2 [6]}}