Edexcel M1 2016 October — Question 8 13 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2016
SessionOctober
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPulley systems
TypeParticle on rough incline, particle hanging
DifficultyStandard +0.3 This is a standard M1 pulley system question with routine application of Newton's second law and friction. Students use F=ma for both particles, apply kinematic equations (v²=u²+2as), and solve simultaneous equations. The tan α = 3/4 requiring sin α = 3/5 and cos α = 4/5 is a common M1 technique. All steps are predictable textbook methods with no novel insight required, making it slightly easier than average.
Spec1.05a Sine, cosine, tangent: definitions for all arguments3.02d Constant acceleration: SUVAT formulae3.03k Connected particles: pulleys and equilibrium3.03l Newton's third law: extend to situations requiring force resolution3.03r Friction: concept and vector form3.03t Coefficient of friction: F <= mu*R model

8. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{6978be48-561b-49a0-a297-c8886ca66c19-20_312_1068_230_438} \captionsetup{labelformat=empty} \caption{Figure 3}
\end{figure} Two particles \(P\) and \(Q\) have masses 2 kg and 3 kg respectively. The particles are attached to the ends of a light inextensible string. The string passes over a smooth light pulley which is fixed at the top of a rough plane. The plane is inclined to horizontal ground at an angle \(\alpha\), where tan \(\alpha = \frac { 3 } { 4 }\). Initially \(P\) is held at rest on the inclined plane with the part of the string from \(P\) to the pulley parallel to a line of greatest slope of the plane. The particle \(Q\) hangs freely below the pulley at a height of 0.5 m above the ground, as shown in Figure 3. The coefficient of friction between \(P\) and the plane is \(\mu\). The system is released from rest, with the string taut, and \(Q\) strikes the ground before \(P\) reaches the pulley. The speed of \(Q\) at the instant when it strikes the ground is \(1.4 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  1. For the motion before \(Q\) strikes the ground, find the tension in the string.
  2. Find the value of \(\mu\).
    END

Question 8:
Part (a):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(1.4^2 = 2a \times 0.5 \Rightarrow a = 1.96 \text{ ms}^{-2}\)M1 A1 M1 for using one or more suvat formulae to produce equation in \(a\) only; A1 for 1.96 (or \(-1.96\))
\(3g - T = 3a\) or \(-3a\)M1 A1 M1 for resolving vertically for \(Q\) (correct no. of terms, condone sign errors); A1 for correct equation
\(T = 23.5\text{ N}\) or \(24\text{ N}\)A1 Third A1 for 23.5 or 24
Part (b):
AnswerMarks Guidance
Working/AnswerMarks Guidance
\(F = \mu R\)B1 B1 for \(F = \mu R\) seen
\(R = 2g\cos\alpha\)M1 A1 M1 for resolving perpendicular to plane (correct no. of terms with \(2g\) resolved); A1 for correct equation (M1A0 for \(R = mg\cos\alpha\))
\(T - 2g\sin\alpha - F = 2a\) or \(-2a\)M1 A1 A1 M1 for resolving parallel to plane (condone sign errors); A1 A1 for correct equation (A1A0 for one error); neither \(T\) nor \(F\) nor \(a\) need substituting
\(\mu = 0.5\)DM1 A1 DM1 dependent on both previous M marks for solving for \(\mu\) (numerical value); A1 for \(\mu = 0.5\) (A0 for 0.499)
# Question 8:

## Part (a):

| Working/Answer | Marks | Guidance |
|---|---|---|
| $1.4^2 = 2a \times 0.5 \Rightarrow a = 1.96 \text{ ms}^{-2}$ | M1 A1 | M1 for using one or more suvat formulae to produce equation in $a$ only; A1 for 1.96 (or $-1.96$) |
| $3g - T = 3a$ or $-3a$ | M1 A1 | M1 for resolving vertically for $Q$ (correct no. of terms, condone sign errors); A1 for correct equation |
| $T = 23.5\text{ N}$ or $24\text{ N}$ | A1 | Third A1 for 23.5 or 24 |

## Part (b):

| Working/Answer | Marks | Guidance |
|---|---|---|
| $F = \mu R$ | B1 | B1 for $F = \mu R$ seen |
| $R = 2g\cos\alpha$ | M1 A1 | M1 for resolving perpendicular to plane (correct no. of terms with $2g$ resolved); A1 for correct equation (M1A0 for $R = mg\cos\alpha$) |
| $T - 2g\sin\alpha - F = 2a$ or $-2a$ | M1 A1 A1 | M1 for resolving parallel to plane (condone sign errors); A1 A1 for correct equation (A1A0 for one error); neither $T$ nor $F$ nor $a$ need substituting |
| $\mu = 0.5$ | DM1 A1 | DM1 dependent on both previous M marks for solving for $\mu$ (numerical value); A1 for $\mu = 0.5$ (A0 for 0.499) |
8.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{6978be48-561b-49a0-a297-c8886ca66c19-20_312_1068_230_438}
\captionsetup{labelformat=empty}
\caption{Figure 3}
\end{center}
\end{figure}

Two particles $P$ and $Q$ have masses 2 kg and 3 kg respectively. The particles are attached to the ends of a light inextensible string. The string passes over a smooth light pulley which is fixed at the top of a rough plane. The plane is inclined to horizontal ground at an angle $\alpha$, where tan $\alpha = \frac { 3 } { 4 }$. Initially $P$ is held at rest on the inclined plane with the part of the string from $P$ to the pulley parallel to a line of greatest slope of the plane. The particle $Q$ hangs freely below the pulley at a height of 0.5 m above the ground, as shown in Figure 3. The coefficient of friction between $P$ and the plane is $\mu$. The system is released from rest, with the string taut, and $Q$ strikes the ground before $P$ reaches the pulley. The speed of $Q$ at the instant when it strikes the ground is $1.4 \mathrm {~m} \mathrm {~s} ^ { - 1 }$.
\begin{enumerate}[label=(\alph*)]
\item For the motion before $Q$ strikes the ground, find the tension in the string.
\item Find the value of $\mu$.

\begin{center}
\begin{tabular}{|l|l|}
\hline

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END &  \\
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\end{tabular}
\end{center}
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2016 Q8 [13]}}