Edexcel M1 2022 June — Question 1 4 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2022
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeDirect collision, find impulse magnitude
DifficultyModerate -0.8 This is a straightforward M1 impulse question requiring only the impulse-momentum equation (Impulse = change in momentum) applied once, with clear given values. It involves basic algebraic manipulation and sign conventions but no problem-solving insight or multi-step reasoning beyond choosing the correct direction convention.
Spec6.03e Impulse: by a force6.03f Impulse-momentum: relation

  1. Two particles, \(P\) and \(Q\), are moving towards each other in opposite directions along the same straight line when they collide directly. Immediately before the collision the speed of \(Q\) is \(2 u\). The mass of \(Q\) is \(3 m\) and the magnitude of the impulse exerted by \(P\) on \(Q\) in the collision is \(4 m u\).
Find
  1. the speed of \(Q\) immediately after the collision,
  2. the direction of motion of \(Q\) immediately after the collision.

Question 1:
Part 1(a):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(-4mu = 3m(v-2u)\) or \(4mu = 3m(-v+2u)\) or \(-4mu = 3m(-v-2u)\) or \(4mu = 3m(v+2u)\)M1A1 Impulse-momentum equation, dimensionally correct, correct no. of terms; condone sign errors but must be attempting a difference of momenta. Allow if they use \(m\) instead of \(3m\)
Speed is \(\frac{2}{3}u\), \(0.67u\) or betterA1 cao (must be positive)
Part 1(b):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Same as its original direction / direction is unchanged / 'same direction' / 'it is the same' / 'opposite to \(P\)'s original direction' / 'towards \(P\)'DB1 Dependent on obtaining either \(\frac{2}{3}u\) or \(-\frac{2}{3}u\) for \(v\) in (a). Allow 'east' or 'to the left' etc. 'motion of \(Q\) is unchanged' is B0
# Question 1:

## Part 1(a):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $-4mu = 3m(v-2u)$ **or** $4mu = 3m(-v+2u)$ **or** $-4mu = 3m(-v-2u)$ **or** $4mu = 3m(v+2u)$ | M1A1 | Impulse-momentum equation, dimensionally correct, correct no. of terms; condone sign errors but must be attempting a difference of momenta. Allow if they use $m$ instead of $3m$ |
| Speed is $\frac{2}{3}u$, $0.67u$ or better | A1 | cao (must be positive) |

## Part 1(b):

| Answer/Working | Marks | Guidance |
|---|---|---|
| Same as its original direction / direction is unchanged / 'same direction' / 'it is the same' / 'opposite to $P$'s original direction' / 'towards $P$' | DB1 | Dependent on obtaining either $\frac{2}{3}u$ or $-\frac{2}{3}u$ for $v$ in (a). Allow 'east' or 'to the left' etc. 'motion of $Q$ is unchanged' is B0 |

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\begin{enumerate}
  \item Two particles, $P$ and $Q$, are moving towards each other in opposite directions along the same straight line when they collide directly. Immediately before the collision the speed of $Q$ is $2 u$. The mass of $Q$ is $3 m$ and the magnitude of the impulse exerted by $P$ on $Q$ in the collision is $4 m u$.
\end{enumerate}

Find\\
(a) the speed of $Q$ immediately after the collision,\\
(b) the direction of motion of $Q$ immediately after the collision.

\hfill \mbox{\textit{Edexcel M1 2022 Q1 [4]}}